In the equation (x-3)2+(y-2)2=16, the center of the circle is... Question 1In the equation (x-3)2+(y-2)²=16, the center of the circle is.(А) (3,2)B (2,3)(с) (3,.2)D (-2,-3)

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Answered: In the equation (x-3)-+(y-2)²=16, the…

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Trigonometry

In the equation (x-3)-+(y-2)²=16, the center of the circle is. (А) (3,2) (в) (2,3) © (-3,-2) D (-2,-3)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter11: Topics From Analytic Geometry

Section: Chapter Questions

Problem 30RE

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Question

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

Two-dimensional figure measured in terms of radius. It is formed by a set of points that are at a constant or fixed distance from a fixed point in the center of the plane. The parts of the circle are circumference, radius, diameter, chord, tangent, secant, arc of a circle, and segment in a circle.

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