Use the solution for solving the questions since they only differ in values In the figure R1 = 120 Q, R2 = R3 = 66.0 Q, R4 = 71.7 Q, and the ideal battery has emf ɛ = 6.00 V. (a) What is the equivalentresistance? What is i in (b) resistance 1, (c) resistance 2, (d) resistance 3, and (e) resistance 4?RAR2R(a) NumberUnits(b) NumberiUnits(c) NumberUnits(d) NumberiUnits(e) NumberiUnits or in parallel to make a 10 N resist-ance that is capable of dissipating at1190CHAPTER 27R1least 5.0 W?R4R3problem demands Ptotal 2 5.0P, so n² must be at least as large as 5.0. Since n must be aninteger, the smallest it can be is 3. The least number of resistors is n = 9.R2In Fig. 27-53, RỊ50.0 N, R4 = 75.0 N, andthe ideal battery has emf E = 6.00 V.(a) What is the equivalent resistance?What is i in (b) resistance 1, (c) resist-ance 2, (d) resistance 3, and (e) resist-•44GO100 N,R2 = R344. (a) Resistors R2, R3, and R4 are in parallel. By finding a common denominator andsimplifying, the equation 1/R = 1/R2 + 1/R3 + 1/R4 gives an equivalent resistance ofFigure 27-53Problems 44 and 48.R,R,R,(50.02)(50.02)(75.02)R=RR +R,R, + RR, (50.0Ω)(50.0Ω) + (50.0Ω)(75.0Ω) + (50.0Ω)(750Ω)=18.8N.ance 4?R1R1Thus, considering the series contribution of resistor R1, the equivalent resistance for thenetwork is Rea = R1 + R = 100 Q + 18.8 Q =118.8 Q × 119 Q.•45 ILW In Fig. 27-54, the resistances1.0 N and R2= 2.0 N,are R1and the ideal batteries have emfsR2(b) i¡ = ɛ/Req = 6.0 V/(118.8 N) = 5.05 × 10² A.R1E1 = 2.0 V and E, = Ez = 4.0 V. Whatare the (a) size and (b) direction (upor down) of the current in battery 1,the (c) size and (d) direction of the(c) iz = (ɛ- V1)/R2 = (ɛ- i¡R¡)/R2 = [6.0V – (5.05 × 10² A)(1002)]/50 2 = 1.90 × 10² A.R1(d) iz = (ɛ- Vi)/R3 = i,R2/R3 = (1.90 × 10² A)(50.0 2/50.0 N) = 1.90 × 10² A.(e) i4 = i1 – i2 – iz = 5.05 × 10² A – 2(1.90 × 10² A) = 1.25 x 10² A.Figure 27-54 Problem 45.

Question

Use the solution for solving the questions since they only differ in values In the figure R1 = 120 Q, R2 = R3 = 66.0 Q, R4 = 71.7 Q, and the ideal battery has emf ɛ = 6.00 V. (a) What is the equivalentresistance? What is i in (b) resistance 1, (c) resistance 2, (d) resistance 3, and (e) resistance 4?RAR2R(a) NumberUnits(b) NumberiUnits(c) NumberUnits(d) NumberiUnits(e) NumberiUnits>>> or in parallel to make a 10 N resist-ance that is capable of dissipating at1190CHAPTER 27R1least 5.0 W?R4R3problem demands Ptotal 2 5.0P, so n² must be at least as large as 5.0. Since n must be aninteger, the smallest it can be is 3. The least number of resistors is n = 9.R2In Fig. 27-53, RỊ50.0 N, R4 = 75.0 N, andthe ideal battery has emf E = 6.00 V.(a) What is the equivalent resistance?What is i in (b) resistance 1, (c) resist-ance 2, (d) resistance 3, and (e) resist-•44GO100 N,R2 = R344. (a) Resistors R2, R3, and R4 are in parallel. By finding a common denominator andsimplifying, the equation 1/R = 1/R2 + 1/R3 + 1/R4 gives an equivalent resistance ofFigure 27-53Problems 44 and 48.R,R,R,(50.02)(50.02)(75.02)R=RR +R,R, + RR, (50.0Ω)(50.0Ω) + (50.0Ω)(75.0Ω) + (50.0Ω)(750Ω)=18.8N.ance 4?R1R1Thus, considering the series contribution of resistor R1, the equivalent resistance for thenetwork is Rea = R1 + R = 100 Q + 18.8 Q =118.8 Q × 119 Q.•45 ILW In Fig. 27-54, the resistances1.0 N and R2= 2.0 N,are R1and the ideal batteries have emfsR2(b) i¡ = ɛ/Req = 6.0 V/(118.8 N) = 5.05 × 10² A.R1E1 = 2.0 V and E, = Ez = 4.0 V. Whatare the (a) size and (b) direction (upor down) of the current in battery 1,the (c) size and (d) direction of the(c) iz = (ɛ- V1)/R2 = (ɛ- i¡R¡)/R2 = [6.0V – (5.05 × 10² A)(1002)]/50 2 = 1.90 × 10² A.R1(d) iz = (ɛ- Vi)/R3 = i,R2/R3 = (1.90 × 10² A)(50.0 2/50.0 N) = 1.90 × 10² A.(e) i4 = i1 – i2 – iz = 5.05 × 10² A – 2(1.90 × 10² A) = 1.25 x 10² A.Figure 27-54 Problem 45.

Accepted Answer

Resistor is an electrical component which limits or reduces the flow of electrons. It is a passive…

In the figure R1 = 120 N, R2 = R3 = 66.0 N, R4 = 71.7 Q, and the ideal battery has emf ɛ = 6.00 V. (a) What is the equivalent resistance? What is i in (b) resistance 1, (c) resistance 2, (d) resistance 3, and (e) resistance 4? R ww