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A: Given:sinx=0.3
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A: Answer
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Q: Prove that the equation sinx = 0.3 has at least one solution in the interval(o, π/2).
A:
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A: We have to find
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Q: how many solutions does (cot(x)-4)(sin(x)-2)(3sin(x)-2)(sin(x))=0 have in the interval [0,2pi]
A: Given trigonometric equation is,
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A: Dear student, since you have posted multiple questions, as per our policy we will answer first…
Q: Find all solutions of the equation in the interval [0,2π). cot x/3=root 3
A: Given:
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- The solution of some second order linear DEQ is exp(-7x)[5sin(1x)+ 7cos(1x)] which can also be expressed as A*exp(-D*x)*sin(F*x+G). Determine A,D,F, and G (degrees).In the interval [0, pi], find the absolute extrema of: g(x) = ex sin x - sin x + cos xUse the false position method to find a root of the equation (e power x) +(2power −x) + 2cos x = 6 in the interval [1, 2] with stopping criterion (Es) = 0.005%
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