In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î + Î +R and an adjacent C-H bond is at the direction B=î-1-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A= 1.01i + 1.07j + 1.09k B = 0.92i + -1.07j + -1.04k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.

In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î + Î +R and an adjacent C-H bond is at the direction B=î-1-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A= 1.01i + 1.07j + 1.09k B = 0.92i + -1.07j + -1.04k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.