Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
In the next chapter, on Gauss's law, we will show that a single infinite, flat, uniformly charged sheet creates an electric field that has a magnitude that is the same everywhere, and that this magnitude is |E| σ/(260) where σ = Q/A, the source charge on the sheet divided by the area of the sheet. As you might expect, the field points due to positively charged sheets points away from the sheet and the field of negatively charged sheets points toward the sheet, and so the field due to a particular sheet points opposite directions on the two sides of that sheet. Consider a set of two such sheets, placed parallel to each other. I have labeled three regions: I to the left of both sheets, II between them, and III to the right of both. Suppose that the sheet on the left has a negative surface charge density of -6.0C/m² while the sheet on the right has a positive surface charge density of +9.0C/m². = I 1

In the next chapter, on Gauss's law, we will show that a single infinite, flat, uniformly charged sheet creates an electric field that has a magnitude that is the same everywhere, and that this magnitude is |E| σ/(260) where σ = Q/A, the source charge on the sheet divided by the area of the sheet. As you might expect, the field points due to positively charged sheets points away from the sheet and the field of negatively charged sheets points toward the sheet, and so the field due to a particular sheet points opposite directions on the two sides of that sheet. Consider a set of two such sheets, placed parallel to each other. I have labeled three regions: I to the left of both sheets, II between them, and III to the right of both. Suppose that the sheet on the left has a negative surface charge density of -6.0C/m² while the sheet on the right has a positive surface charge density of +9.0C/m². = I 1

icon
Related questions
Question
= where o = In the next chapter, on Gauss's law, we will show that a single infinite, flat, uniformly charged sheet creates an electric field that has a magnitude that is the same everywhere, and that this magnitude is |E| σ/(2€0) Q/A, the source charge on the sheet divided by the area of the sheet. As you might expect, the field points due to positively charged sheets points away from the sheet and the field of negatively charged sheets points toward the sheet, and so the field due to a particular sheet points opposite directions on the two sides of that sheet. Consider a set of two such sheets, placed parallel to each other. I have labeled three regions: I to the left of both sheets, II between them, and III to the right of both. Suppose that the sheet on the left has a negative surface charge density of -6.0C/m² while the sheet on the right has a positive surface charge density of +9.0C/m². |·| (a) Draw a diagram of the sheets and show the direction of the individual field created by each of them in each region I, II, and III. Make sure you clearly label which sheet is creating which arrow in your diagram. NOTE that the individual field by one sheet is not affected by the presence of the other sheet. (b) Find the magnitude of each of the fields you drew in part a, above, using the text's results for large plates. (c) Use superposition (the vector sum of the individual fields you have drawn at a given test point) to find the magnitude and direction of the total field in each region. |-|
Transcribed Image Text:= where o = In the next chapter, on Gauss's law, we will show that a single infinite, flat, uniformly charged sheet creates an electric field that has a magnitude that is the same everywhere, and that this magnitude is |E| σ/(2€0) Q/A, the source charge on the sheet divided by the area of the sheet. As you might expect, the field points due to positively charged sheets points away from the sheet and the field of negatively charged sheets points toward the sheet, and so the field due to a particular sheet points opposite directions on the two sides of that sheet. Consider a set of two such sheets, placed parallel to each other. I have labeled three regions: I to the left of both sheets, II between them, and III to the right of both. Suppose that the sheet on the left has a negative surface charge density of -6.0C/m² while the sheet on the right has a positive surface charge density of +9.0C/m². |·| (a) Draw a diagram of the sheets and show the direction of the individual field created by each of them in each region I, II, and III. Make sure you clearly label which sheet is creating which arrow in your diagram. NOTE that the individual field by one sheet is not affected by the presence of the other sheet. (b) Find the magnitude of each of the fields you drew in part a, above, using the text's results for large plates. (c) Use superposition (the vector sum of the individual fields you have drawn at a given test point) to find the magnitude and direction of the total field in each region. |-|
Expert Solution
Step 1

The direction of the electric field is away from the positive charge and is towards the negative charge. 

(a) The direction of the individual field created in three regions 

The electric field due to infinite charge sheet with charge density -6.0 C/m2 is E1 and the electric field due to infinite charge sheet with charge density 9.0 C/m2 is E2.

The diagram below shows the direction of electric field due to infinite charge sheet with charge density -6.0 C/m2 

The direction of electric field in region I is in right direction, in region II the direction is towards the negative charge  so it is in left direction and the electric field in region III is also towards left direction because the direction of electric field is towards negative charge. 

Advanced Physics homework question answer, step 1, image 1

The diagram below shows the direction of electric field due to infinite charge sheet with charge density 9.0 C/m2 

The direction of electric field in region I is in left direction, in region II the direction is away from the positive charge  so it is in left direction and the electric field in region III is also towards right direction because the direction of electric field is away from positive charge. 

Advanced Physics homework question answer, step 1, image 2

 

steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer