In the two-layer uniformly varying field electrode system separated by the X=0 plane, the amplitude of the electric field vector in the first layer is 80kV/cm and the angle it makes with the perpendicular component is 〖20〗^0. Since the relative electric constants of the layers are 4 and 2, respectively, calculate the tangential component of the electric field in the second layer.

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Example 2.24)

In the two-layer uniformly varying field electrode system separated by the X=0 plane, the amplitude of the electric field vector in the first layer is 80kV/cm and the angle it makes with the perpendicular component is 〖20〗^0. Since the relative electric constants of the layers are 4 and 2, respectively, calculate the tangential component of the electric field in the second layer.

In the two layer uniformly varying field electrode system separated by the X-0 plane, the amplitude of the electric field
vector in the first layer is 80KV/cm and the angle it makes with the perpendicular component is (20) ^0. Since the
relative electric constants of the layers are 4 and 2, respectively, calculate the tangential component of the electric field
in the second layer.
a)
22 KV/cm
b)
19 kV/cm
c)
27 kV/cm
d)
18 KV/cm
e)
29 kV/cm
Transcribed Image Text:In the two layer uniformly varying field electrode system separated by the X-0 plane, the amplitude of the electric field vector in the first layer is 80KV/cm and the angle it makes with the perpendicular component is (20) ^0. Since the relative electric constants of the layers are 4 and 2, respectively, calculate the tangential component of the electric field in the second layer. a) 22 KV/cm b) 19 kV/cm c) 27 kV/cm d) 18 KV/cm e) 29 kV/cm
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