#include int main(void) { int t; /* number of toonies int 1; /* number of loonies /* number of quarters int qi int d; /* number of dimes int n; /* number of nickels /* you fill in the rest */ return 0; } Your program should prompt for and print out relevant information in the following form: How many toonies do you have? 3 have? 1 How many loonies How many quarters How many dimes How many nickels You entered: do you do you have? 3 do you have? 8 do you have? 7 3 toonie(s) 1 loonie (s) 3 quarter (s) 8 dime(s) 7 nickel(s) The value of your 22 coins is $8.90

#include int main(void) { int t; /* number of toonies int 1; /* number of loonies /* number of quarters int qi int d; /* number of dimes int n; /* number of nickels /* you fill in the rest */ return 0; } Your program should prompt for and print out relevant information in the following form: How many toonies do you have? 3 have? 1 How many loonies How many quarters How many dimes How many nickels You entered: do you do you have? 3 do you have? 8 do you have? 7 3 toonie(s) 1 loonie (s) 3 quarter (s) 8 dime(s) 7 nickel(s) The value of your 22 coins is $8.90

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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This is what I have so far 1. Too many arguments. #include <stdio.h> Void simple(); Int main() { Int n; simple(1,2,3,4,5,6,7,8,9,10,11,12); Return0; } Void simple(int n){ printf(“%d”,n); } What does this do? This code prints the first argument passed to the simple function called. That is (1). Does the extra argument break the code? No, the extra argument does not break the code as the remaining argument are ignored by the function. Which argument(s) gets printed? The arguments are printed in the order they are called in the function. Here, the argument to be passed first is 1 and that is printed. The first argument is printed. Why? This is because the remaining arguments are evaluated by the function and then ignored. 2. Too few parameters
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int main() { E(); C(); E(); } void B() {...} void C() {..} void D() {..} void E() { B(); D(); } A variable declared in function B and only in function B is accessible in?