Index 1 2 3 4 Value using Quadratic Overflow is processed Index 0 1 2 3 4 Value 0 5 6 probing. 5 6 7 8 9 10 10 7 8 9
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- Consider the following cuckoo hashing with 2 tables. Both tables have asize of 11.The hashing function of the first table is:h1 (k) = kmod 11The hashing function of the second table is:ha(k) = 141 mod 11(Note: mod is the modulo operation. It returns the remainder of a division.For example, "3 mod 11 = 3" and "20 mod 11 = 9")The following sequence of insert operations are performed:• Insert 50• Insert 53• Insert 75Which of the following is TRUE after the above operations? 75 is in the first table 50 is in the second table1. Give the contents of the resulting hash table when you insert items with the keys L A G U N I V E R S in that order into an initially empty table of size M = 16 using linear probing. Use the hash function 11k mod M to transform the kth letter of the alphabet into a table index. Example: hash(J) hash(10) = 110 % 16 = 14 Show the detailed solution for each key and plot the items in the hash table.Question 5 Assume you have a hash table of size 13, insert the following keys using open addressing with linear probing, assuming that the H(Key) = key % size and the bucket size is equal to 1. Keys: 25, 66, 710, 150, 82, 111, 70,17 a. index key 0 1 66 2 3 4 82 5 70 6 17 7 150 8 710 9 111 10 11 25 12 b. index key 1 2 66 3 4 5 82 6 70 7 17 8 150 9 710 10 111 11 12 13 25 c. index key 0 1 66 2 3 4 82 5 70 6 17 7 150 8 111 9 710 10 11 12 25 d. index key 0 1 66 2 3 4 82 5 70 6 17 7 150 8 710 9 111 10 11 12 25
- Insert the following data into a hash table implemented using linear openaddressing. Assume that the buckets have three slots each. Make use of the hashfunction h(X) = X mod 9.{17, 09, 34, 56, 11, 71, 86, 55, 22, 10, 4, 39, 49, 52, 82, 13, 40, 31, 35, 28, 44}Show what occurs when the keys 5, 28, 19, 15, 20, 33, 12, 17, and 10 are inserted into a hash table with collisions addressed by chaining. If the table has nine slots, then the hash function should be h.k/D k mod nine.Insert keys {10, 22, 11, 31, 24, 88, 38, 21} into an empty hash table with CAPACITY = 10 using quadratic probing (c1=0 and c2=1) to resolve collision (You shouldn't use a for/while loop except to increment the value of i for quadratic probing). Use the hash function is h(k, i) = (h’(k) + c1* i + c2* i^2) mod 10 and h’(k) = k mod 10.
- Answer the following ture or false question 1. The 9-entry hash table that results from using the hash function, h(i) = (2i+7) mod 9, to hash the keys 12, 5, 13, 4, 10, 19, 8, 3, and 28, assuming collisions are handled by linear probing as follows: 0 1 2 3 4 5 6 7 8 10 19 3 28 12 8 13 4 5 Group of answer choices True False 2. Here is how the built-in sum function can be combined with Python’s comprehension syntax to compute the sum of all numbers in an n x n data set, represented as a list of lists: sum(sum(subset) for subset in data) Group of answer choices True False 3. Here is the comparison for asymptotic growth rate: (logn) < (n) < (nlogn) < (n^2) < (n^3) < (2^n) Group of answer choices True False 4. Here is the Python’s list comprehension syntax to produce the list of this 26 characters ['a', 'b', 'c', ..., 'z']: [chr(k) for k in range(97, 123)] Group of answer choices True FalseGiven the array of size 17, and the hashing function h(x) = x%17, at which array location would data with key value 86 be stored? Assuming 35 and 69 have already been inserted in the array and the quadratic probing is used for collision. Question 10 options: 6 5 4 320 a) Given a hashing function hash(x) = ((x * x) + x) % 11, Insert the value 17 into each hash table using the rules specified below. Note that some of the boxes in each hash table are already full. If there’s a collision, start the probing at i = 0 and increment from there if you collide. b) After we insert our new data (that 17) into these hash tables, should we resize and rehash the values? Why or Why not? c) If this was a hash table using separate chaining instead of linear probing, would it be time to rehash after we insert 17?
- 1. Given the input set A = {1, 2, 3, 4, 5} and output set B = {1, 2, 3, 4}, is it possible to find a hash function H from A to B that has no hash collision, i.e., ∀ a1, a2 ∈A, H(a1) ≠H(a2) If yes, please give the function. Otherwise, please explain. (Hint: pigeonhole principle) 2. Bob has uploaded a very large file in his online file storage. Later, he needs to download the file and verify whether the file has been modified. A. If a cryptographic hash function can be applied, briefly describe how to use a hash function to file integrity checking? B. Why doesn't Bob save the whole big file locally and directly compare it to the file he downloads?Suppose that we are using extendable hashing on a file that contains recordswith the following search-key values:2, 3, 5, 7, 11, 17, 19, 23, 29, 31Show the extendable hash structure for this file if the hash function is h(x) = xmod 8 and buckets can hold three records.If the sizeof hash table is 11, the hash function is H(key)=(2*key+1)MOD 11,open addressing, square probing. According to the keywords sequence (19,21,10,7,23,32,17,15,11,22), please insert these keywords in the hash table from 0-10 .