Indicate whether each history is serializable. H₁ ={R₁(x), W₁(x), R₂(x), R₁(y), W₂(x), W1(y), R₂(y), W₂(y)} H₂={R₁(x), R₂(x), W₂(x), R₂(y), W1(x), R₁(v), W₁(y), W₂(y)} H1 is H2 is
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- Take, for instance, an airline database using a technique called "snapshot isolation." If the airline's overall performance is enhanced, then non-serializable executions may be tolerated.Take, for instance, an airline database using a technique called "snapshot isolation." If the airline's overall performance improves, non-serializable executions may be tolerated.Is it conceivable that a single process may get stuck in a stalemate state? Justify your replies.
- How does encapsulation and decapsulation occur in the OSI model, and why is it important for data transmission?Even though there are supposed to be seven in the OSI reference model, that's not necessarily the case. Why would we want to use fewer layers if we can avoid it? Is there anything that may go wrong if we used fewer layers?Suppose (X[mX]+Y [mY ]) > 0. What can you infer about each of the four subproblems (namely, (X1, Y1), (X1, Y2), (X2, Y1), and (X2, Y2))? Clearly identify the ones that do not have to solved anymore, and those that still have to be solved. Briefly justify.
- A chain of many-to-one connections may be used as the building blocks for the construction of a link like the second course. Does the connection have a limit of many-to-one cardinality because of the limits imposed by the main key and the foreign key? What gives you reason to think that to be the case?(2)How many safe sequences are there for the above snapshot? Briefly justify your answer. (3)If P1 requests an additional instance of each of A and C, that is, P1's request becomes (2, 4, 6), will this request result in a deadlock? If the answer is no, give a safe sequence. If the answer is yes, identify the processes that will be involved in the deadlock. Show your work.10. Describe the behaviour of the following machine, which begins with a blank tape, with the machine in configuration α. Configuration Behavior m-config symbol operation final m-config α none R P1 β α 1 R P0 β α 0 HALT none β 1 R P1 α β 0 R P0 α
- Provide a case in favor of deep access as opposed to shallow access from the perspective of a programmer; try to sidestep a discussion of performance.There are distinctions between hard and symbolic linkages.iIllustrate how a binary semaphore can be used to implement mutual exclusion among n processes.