i need the answer quickly Ineed the output step bystep and clear line please eThe Characteristic impedance isR+jwLV G+jwCZo6.74x10+j22.1056%3D0.29x 10 6+j6.28x8.7x10

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Answered: The Characteristic impedance is R+jwL V…

Trigonometry (MindTap Course List)

10th Edition

ISBN:9781337278461

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Exponential And Logarithmic Functions

Section5.5: Exponential And Logarithmic Models

Problem 6ECP: Find the intensities of earthquakes whose magnitudes are aR=6.0andbR=7.9.

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Tsunami Waves and BreakwatersThis is a continuation of Exercise 16. Breakwaters affect wave height by reducing energy. See Figure 5.30. If a tsunami wave of height H in a channel of width W encounters a breakwater that narrows the channel to a width w, then the height h of the wave beyond the breakwater is given by h=HR0.5, where R is the width ratio R=w/W. a. Suppose a wave of height 8 feet in a channel of width 5000feet encounters a breakwater that narrows the channel to 3000feet. What is the height of the wave beyond the breakwater? b. If a channel width is cut in half by a breakwater, what is the effect on wave height? 16. Height of Tsunami WavesWhen waves generated by tsunamis approach shore, the height of the waves generally increases. Understanding the factors that contribute to this increase can aid in controlling potential damage to areas at risk. Greens law tells how water depth affects the height of a tsunami wave. If a tsunami wave has height H at an ocean depth D, and the wave travels to a location with water depth d, then the new height h of the wave is given by h=HR0.25, where R is the water depth ratio given by R=D/d. a. Calculate the height of a tsunami wave in water 25feet deep if its height is 3feet at its point of origin in water 15,000feet deep. b. If water depth decreases by half, the depth ratio R is doubled. How is the height of the tsunami wave affected?
In trying to minimise errors that come with using a tape in linear measurements, Mapalo suggested to the class that an EDM be used to compute the distance from BM1 to point A. A distance of 2122.241m was measured. Given that a frequency of 1.4985MHz was used, speed of light c = 299792458m/s, the refraction index of 1.0003 and that the effective wavelength measures to a centimetre, determine the phase measurement (i.e. Phase Distance and the corresponding Phase angle)

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The Characteristic impedance is R+jwL V G+jwC Z. 6.74x10°+j22.1056 0.29x 10 6+j6.28x8.7x10