Inside one leaf of the three-leaved rose r = cos(30).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 20T
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Hello,

Can someone please solve problem 4? Thanks

For the next two exercises, replace the polar equations with equivalent Cartesian equations. Then
describe or identity the curve.
1 r² sin(20) = 2
2 r2 cos 0 - sin 0
For the next three exercises, calculate the area of the region.
3 Bounded by the circle r = 2 sin for T/4 ≤0</2.
4 Inside one leaf of the three-leaved rose r = cos(30).
5
Inside the circle r = 4 sin and below the horizontal line r = 3 csc 0.
Transcribed Image Text:For the next two exercises, replace the polar equations with equivalent Cartesian equations. Then describe or identity the curve. 1 r² sin(20) = 2 2 r2 cos 0 - sin 0 For the next three exercises, calculate the area of the region. 3 Bounded by the circle r = 2 sin for T/4 ≤0</2. 4 Inside one leaf of the three-leaved rose r = cos(30). 5 Inside the circle r = 4 sin and below the horizontal line r = 3 csc 0.
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