INSTRUCTION: Provide Descriptive Statistics using the Data Analysis in Excel for the “Systolic Blood Pressure” set of data. Copy the result of the Descriptive Statistics in a short bond paper. Based on the dataset, what measure of central tendency (Mean, Median or Mode) should be used and explained? Interpret also the values in relation to Skewness and Kurtosis.
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- The union of two sets is defined as a set of elements that are present in at least one of the sets. How is this similar to the definition used for the union of two events from a probability model? How is it different?3.273525429 3.725058267 3.193881287 3.380595777 3.849062312 2.688788698 4.521501366 2.876926464 3.202865171 3.760862809 3.648737967 3.155042169 3.047772295 2.331491399 2.43426651 3.316262576 3.33570391 3.123784316 1.983014564 4.026381813 2.819851735 3.020835161 3.963952045 3.434812572 2.530150764 3.501124236 2.723868073 3.734018756 3.07485433 2.945439985 2.963046282 3.301251136 3.806637216 2.495620331 2.99022362 2.548798319 2.849586988 3.554039618 3.565046584 3.383944772 2.895875003 3.96006813 3.744978387 4.034873151 3.394484477 4.637022161 3.085000083 3.945715143 2.590540526 3.593019815 Data from sheet 5Date DJIA S&P 500 Day 1 35405.24 4536.54 Day 2 35629.33 4579.38 Day 3 35111.16 4467.44 Day 4 35089.74 4510.53 Day 5 35091.13 4493.87 Day 6 35462.78 4511.54 Day 7 35768.06 4577.18 Day 8 35241.59 4514.08 Day 9 34738.06 4408.64 Day 10 34566.17 4411.67 Day 11 34988.84 4461.07 Day 12 34934.27 4485.01 Day 13 34312.03 4390.26 Day 14 34079.18 4358.87 Day 15 33596.61 4314.76 Day 16 33131.76 4235.50 Day 17 33223.83 4278.70 Day 18 34058.75 4394.65 Day 19 33892.60 4363.94 Day 20 33294.95 4316.26 Day 21 33891.35 4396.54 Day 22 33794.66 4353.49 Day 23 33614.80 4318.87 Day 24 32817.38 4211.09 Day 25 32632.64 4180.70 Day 26 33286.25 4287.88 Day 27 33174.07 4249.52 Day 28 32944.19 4194.31 Day 29 32945.24 4183.11 Day 30 33544.34 4252.45 Day 31 34063.10 4367.86 Day 32 34480.76 4421.67 Day 33 34754.93 4473.12 Day 34 34552.99 4471.18 Day 35 34807.46 4521.61 Day 36 34358.50 4466.24 Day 37 34707.94 4510.16 Day 38 34861.24 4553.06…
- Male Female27,329 22,49814,596 24,5893,890 5,06827,315 16,72525,067 10,3808,480 16,57219,490 10,75516,334 19,12228,183 11,82721,356 18,61212,674 15,73210,066 11,42311,288 17,79220,679 24,76719,722 6,359369 19,57118,284 21,81211,653 19,68618,981 18,29415,412 13,48515,839 31,24320,391 9,4316,069 16,1216,072 4,22624,527 12,6649,492 20,22511,618 14,59813,916 22,04613,081 20,08517,460 11,13913,491 35,7097,630 8,54121,263 9,82216,455 12,38511,590 28,05515,409 19,22816,827 16,21710,596 17,72618,005 20,00612,428 16,58313,727 19,8574,706 14,49917,168 17,97412,641 17,22015,661 28,75616,855 38,40718,490 25,78537,993 33,38319,196 25,06447,688 30,26225,062 18,14310,357 7,59515,653 23,8969,962 16,4425,377 16,53619,537 26,129Company Competitor 1383 1153 2022 1067 2429 1296 901 1406 2219 1254 1896 1335 1910 1204 1539 1076 2048 1246 2881 1098 2395 1258 1349 955 2052 954 2675 1363 1588 1022 2704 1155 3148 1807 2822 1295 2217 1116 2260 1323 3040 1326 3137 1107 2977 1163 2599 1254 2412 1017 3187 938 2598 1270 2995 1042 3046 1318 3858 1497 2438 750 3243 1380 2764 1053 2944 932 3324 1097 2797 1193 3914 1271 2766 843 2273 780 3052 1095 3202 1290 3672 937 3957 1390 3274 1056 3788 1235 3502 1235 2942 999 3078 1066 3196 641 3141 1322 3579 1289 3895 1060 above is the excel data, please solve the excel part with formulas and explanation, thanks4. The number of passengers (in thousands) for the leading U.S. passenger airlines in 2004 is indicated below. 91,570 86,755 81,066 70,786 55,373 42,400 40,551 21,119 16,280 14,869 13,659 13,417 13,170 12,632 11,731 10,420 10,024 9,122 7,041 6,954 6,406 6,362 5,930 5,585 5,427• Use the data to construct a grouped frequency distribution and a cumulative frequency distribution with a reasonable number of classes and comment on the shape of the distribution using graph.
- 1) Country Population Cases, total Deaths, total China 1,439,323,776 93,329 4,750 India 1,380,004,385 9,392,919 136,696 USA 331,002,651 12,939,666 262,736 Indonesia 273,523,615 527,999 16,646 Pakistan 220,892,340 392,356 7,942 Brazil 212,559,417 6,238,350 171,974 Nigeria 206,139,589 67,330 1,171 Bangladesh 164,689,383 460,619 6,580 Russia 145,934,462 2,269,316 39,527 Mexico 128,932,753 1,090,675 104,873 Japan 126,476,461 144,653 2,106 Ethiopia 114,963,588 108,930 1,695 Philippines 109,581,078 427,797 8,333 Egypt 102,334,404 115,183…Calculate the point prevalence for Alzheimer’s disease among individuals 65 years of age or older in a county that has 200,000 individuals who are 65 years of age or older, if 22,223 individuals who are 65 years of age or older have the disease. 0.0111 0.1111 0.8889 0.9889What is pythagrom theriom
- An insurance company classifies its policy holders according to age, sex,and marital status. Of 500 policy holders, it was found out that: 350 weremarried, 240 were under 25, 230 were married men, 110 were marriedand under 25, 100 were men under 25, 40 were married men under 25,and 10 were single women 25 or older. How many policy holders weremen?Listed below are amounts (in millions of dollars) collected from parking meters by a security service company and other companies during similar time periods. Security Service Company:Security Service Company: 1.51.5 1.71.7 1.41.4 1.31.3 1.61.6 1.41.4 1.71.7 1.51.5 1.41.4 1.61.6 Other Companies:Other Companies: 1.71.7 1.91.9 1.61.6 1.81.8 1.61.6 1.81.8 1.51.5 1.61.6 1.91.9 1.61.6 Please show me how to locate the coefficient of variation for each of the two samples, then compare the variation, using the coefficient of variation for the amount collected by the security service company what is the percentage?Petal length (in cm) of Iris virginica: x1; n1 = 36 5.0 5.6 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.7 5.3 5.3 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.6 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.7 Let ?1 be the population mean for x1 and let ?2 be the population mean for x2. Find a 99% confidence interval for ?1 − ?2. (Round your answers to two decimal places.) lower limit: upper limit: Which distribution did you use? Why? A) The standard normal distribution was used because ?1 and ?2 are unknown. B) The Student's t-distribution was used because ?1 and ?2 are known. C) The Student's t-distribution was used because ?1 and ?2 are unknown. D) The standard normal distribution was used because ?1 and ?2 are known. Do you need information about the petal length…