Integral using trigonometric sub The answer in the integral is: sin(20) + C 8 4 If x= 2sece then x/2 = sec 0 which is hypotenuse/adjacent. That means hypotenuse=xand adjacent=2. Which left us through Pythagorean theorem with sq rt of x^2-4 as the opposite. Now what will be the value of 0 and the sin(20)to be put in the equation? After that, what will be its derivative so I can make sure I go back the original integral.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 49E
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Integral using trigonometric sub
The answer in the integral is:
sin(20)
+ C
4
If x= 2sece then x/2 = sec 0 which is hypotenuse/adjacent. That means hypotenuse=xand adjacent=2.
Which left us through Pythagorean theorem with sqrt of x^2-4 as the opposite. Now what will be the
value of 0 and the sin(20)to be put in the equation? After that, what will be its derivative so I can
make sure I go back the original integral.
Transcribed Image Text:Integral using trigonometric sub The answer in the integral is: sin(20) + C 4 If x= 2sece then x/2 = sec 0 which is hypotenuse/adjacent. That means hypotenuse=xand adjacent=2. Which left us through Pythagorean theorem with sqrt of x^2-4 as the opposite. Now what will be the value of 0 and the sin(20)to be put in the equation? After that, what will be its derivative so I can make sure I go back the original integral.
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