is 2 Sinh xt sinh (۱) Let y emx (to) be the trial solution to the Corresponding homogeneous equation of (1) .: The auxiliary equation is Solution: The given ODE (04-1) y = HOW DID HE GET THE VALUE INSIDE THE CIRCLE wit the complementary function is y c₁ex + ₂ēx + C3 Cosx + C4 Sinx are arbitrary constante. (4 the particular solution de (Sinhx) where C₁, C₂, C3, C2 > 2.1 = 2 D4-1 1 2 1 + X B-T (sinx) ) + x 4D3 (sinx)

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