is dropped s(t) = -16t² + vot + so (a) Determine the position and velocity functions for the coin. s(t) = -161²+1323 v(t) = -32t top feet tall. Use the position function below for ree-falling objects. (b) Determine the average velocity on the interval [3, 4]. -112 ft/s (c) Find the instantaneous velocities when t = 3 seconds and t = 4 seconds. V(3) = -96 v(4) = -128 ft/s ft/s (d) Find the time required for the coin to reach the ground level. (Round your answer to three decimal places.) t = 9.09 X S (e) Find the velocity of the coin at impact. (Round your answer to three decimal places.) -290.88 X ft/s

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter2: Functions
Section2.4: Average Rate Of Change Of A Function
Problem 4.2E: bThe average rate of change of the linear function f(x)=3x+5 between any two points is ________.
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A silver dollar is dropped from the top of a building that is 1323 feet tall. Use the position function below for free-falling objects.
s(t) = -16t² + vot + so
(a) Determine the position and velocity functions for the coin.
s(t) = -161²+ 1323
v(t) -32t
(b) Determine the average velocity on the interval [3, 4].
-112
ft/s
(c) Find the instantaneous velocities when t = 3 seconds and t = 4 seconds.
V(3) = -96
v(4) = -128
ft/s
ft/s
(d) Find the time required for the coin to reach the ground level. (Round your answer to three decimal places.)
t = 9.09
X S
(e) Find the velocity of the coin at impact. (Round your answer to three decimal places.)
-290.88
X ft/s
Transcribed Image Text:A silver dollar is dropped from the top of a building that is 1323 feet tall. Use the position function below for free-falling objects. s(t) = -16t² + vot + so (a) Determine the position and velocity functions for the coin. s(t) = -161²+ 1323 v(t) -32t (b) Determine the average velocity on the interval [3, 4]. -112 ft/s (c) Find the instantaneous velocities when t = 3 seconds and t = 4 seconds. V(3) = -96 v(4) = -128 ft/s ft/s (d) Find the time required for the coin to reach the ground level. (Round your answer to three decimal places.) t = 9.09 X S (e) Find the velocity of the coin at impact. (Round your answer to three decimal places.) -290.88 X ft/s
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