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- What is the correct answer in the following?Write the code for the following proofs using LEAN Theorem ProverCorrect answer will be upvoted else Multiple Downvoted. Computer science. pick a non-void adjacent substring of s that contains an equivalent number of 0's and 1's; flip all characters in the substring, that is, supplant all 0's with 1's, as well as the other way around; turn around the substring. For instance, think about s = 00111011, and the accompanying activity: Pick the initial six characters as the substring to follow up on: 00111011. Note that the number of 0's and 1's are equivalent, so this is a lawful decision. Picking substrings 0, 110, or the whole string would not be imaginable. Flip all characters in the substring: 11000111. Invert the substring: 10001111. Find the lexicographically littlest string that can be gotten from s after nothing or more tasks. Input The primary line contains a solitary integer T (1≤T≤5⋅105) — the number of experiments. Every one of the accompanying T lines contains a solitary non-void string — the input string s for…
- please code in python Here is another recursion example, but with less guidance. Write a function log2(x), which gives an integer approximation of the log base 2 of a positive number x, but it does so using recursion. Use a base case where you return 0 if x is 1 or less. In the general case, add 1 to the answer and divide x by 2. (This is purposely vague so you can figure it out yourself.)is it possible to change this function from recursive to iterative one? Any help would be greatly appreciated.57. What is the postfix of the following infix expression? 3 / A + (B + 12) - C. Group of answer choices 3 A + B + 12 C - 3+A B 12 + C - 3 A + B 12 + C - 3 A + B 12 + - C 3 A + + B 12 C -
- Please solve the following recursion question in Java.Which of the following statement(s) is/are correct about recursion? Group of answer choices A.indication of good use of recursion: difficulty to trace down the sequence of recursive calls B.gives cleaner code but has high cost C.never be used as substitute for a simple ‘for’ loop D.bad idea to use it to evaluate simple mathematical functions. E.All of the aboveUsing R, I need to create a code that checks whether a number x is a prime number or not using RECURSION ONLY (while, for, and any iterative operators are not allowed. I made one but it seems that my code has a problem when I run it : is_prime <- function (x) { divisor <- 2 divisor_check <- function (x, divisor) { if (x <= 2) { if (x == 2){ return(TRUE) } else { return(FALSE) } } else if (x %% divisor == 0) { return(FALSE) } else if (divisor * divisor > x) { return(TRUE) } else if (x == 0 || x != floor(x)){ return(NULL) } else { return(FALSE) } } divisor_check(x, divisor+1)} above is the code and when I run it, the results are as follows: > is_prime(1) [1] FALSE > is_prime(2) [1] TRUE > is_prime(3) [1] FALSE > is_prime(4) [1] TRUE > is_prime(5) [1] TRUE
- The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.The factorial of a positive integer n —which we denote as n!—is the product of n and the factorial of n 1. The factorial of 0 is 1. Write two different recursive methods in Java that each return the factorial of n. Analyze your algorithm in Big-Oh notation and provide the appropriate analysis, ensuring that your program has a test class.I am working on this recursive function, and I am drawing a blank. Line 15 else if(s.charAt(0) != s.length () -1 && ............ )) Is there a String method that looks for intergers ? Suppose to look to see if it is the last value and if it is a Integer, if it is , add the vaules that intergers together for a total sum public class Finder { //Write two recursive functions, both of which will parse any length string that consists of digits and numbers. Both functions //should be in the same class and have the following signatures. //use the if/else statement , Find the base case and -1 till you get to base case //recursive function that adds up the digits in the String public static int sumIt(String s) { int sumOfNumbers =0; //if String length is less or equal to 1 retrun 1. for (int i = 0; i >= 0 ;i++) if (s.length()<= 1)//Base case = 1 return 1; //else if the CharAt(value in index at 0 = 1) is not equal to the last vaule in the string else if(s.charAt(0) != s.length ()…