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Is the following argument correct? If so, write "Yes it is correct". If not, write a sentence or two explaining the error. 2 The argument: we give the first step towards computing vV 4 - v dy. We use the substitution -1 = 4- y?, so ,so du = - 2y dy. Considering the bounds, at y = -1 we have u = 3 and at y = 2 we have u du 1 | u72 du. (In order to finish, 2 = 0. So after substitution the integral becomes -2 E, we would use the FTC and the power rule for integrals.)

Is the following argument correct? If so, write "Yes it is correct". If not, write a sentence or two explaining the error. 2 The argument: we give the first step towards computing vV 4 - v dy. We use the substitution -1 = 4- y?, so ,so du = - 2y dy. Considering the bounds, at y = -1 we have u = 3 and at y = 2 we have u du 1 | u72 du. (In order to finish, 2 = 0. So after substitution the integral becomes -2 E, we would use the FTC and the power rule for integrals.)

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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Is the following argument correct? If so, write "Yes it is correct". If not, write a sentence or two explaining the error. 2 The argument: we give the first step towards computing yv 4 - y dy. We use the substitution -1 = 4 – - v, so du = - - 2y dy. Considering the bounds, at y = -1 we have u = 3 and at y = 2 we have u u du 1 Vu -2 = 0. So after substitution the integral becomes du. order to finish, %3D 2 we would use the FTC and the power rule for integrals.)
Transcribed Image Text:Is the following argument correct? If so, write "Yes it is correct". If not, write a sentence or two explaining the error. 2 The argument: we give the first step towards computing yv 4 - y dy. We use the substitution -1 = 4 – - v, so du = - - 2y dy. Considering the bounds, at y = -1 we have u = 3 and at y = 2 we have u u du 1 Vu -2 = 0. So after substitution the integral becomes du. order to finish, %3D 2 we would use the FTC and the power rule for integrals.)
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