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It is decided to extract A from a feed containing 20 mol % A and 80 mol% B in two ideal cross current stages as shown below using equal amount of pure solvent where. X = moles of A per mole of B in raffinate Y * = moles Cin each stage. Components B and C are immiscible. 60% of A in the feed is extracted in Stage 1. The equilibrium relation is given by Y = 1.5 X of A per mole of C in extract in equilibrium with raffinate. Selvent Solvent The mol % of A in raffinate from Stage 2 is off to second decimal place). (rounded Raffinate affinate2 Feed Stage 1 Stage 2 Extract 1 Extract 2

It is decided to extract A from a feed containing 20 mol % A and 80 mol% B in two ideal cross current stages as shown below using equal amount of pure solvent where. X = moles of A per mole of B in raffinate Y * = moles Cin each stage. Components B and C are immiscible. 60% of A in the feed is extracted in Stage 1. The equilibrium relation is given by Y = 1.5 X of A per mole of C in extract in equilibrium with raffinate. Selvent Solvent The mol % of A in raffinate from Stage 2 is off to second decimal place). (rounded Raffinate affinate2 Feed Stage 1 Stage 2 Extract 1 Extract 2

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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It is decided to extract A from a feed containing 20 mol % A and 80 mol% B in two ideal cross current stages as shown Y* = 1.5 X below using equal amount of pure solvent where. X = moles of A per mole of B in raffinate Y * = moles C in each stage. Components B and C are immiscible. 60% of A in the feed is extracted in Stage 1. The equilibrium relation is given by of A per mole of C in extract in equilibrium with raffinate. Selvent Solvent The mol % of A in raffinate from Stage 2 is off to second decimal place). (rounded Feed Raffinate 1 Raffinate 2 Stage 1 Stage 2 Extract 1 Extract 2
Transcribed Image Text:It is decided to extract A from a feed containing 20 mol % A and 80 mol% B in two ideal cross current stages as shown Y* = 1.5 X below using equal amount of pure solvent where. X = moles of A per mole of B in raffinate Y * = moles C in each stage. Components B and C are immiscible. 60% of A in the feed is extracted in Stage 1. The equilibrium relation is given by of A per mole of C in extract in equilibrium with raffinate. Selvent Solvent The mol % of A in raffinate from Stage 2 is off to second decimal place). (rounded Feed Raffinate 1 Raffinate 2 Stage 1 Stage 2 Extract 1 Extract 2
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