It is known that the population range equals 60. With a 95% confidence level, the sample size that needs to be taken if the desired margin of error is 4 or less is
Q: If n = 340 and p^=0.92, find the margin of error at a 90% confidence level E= Give your answer to…
A: Given,n=340p^=0.921-p^=1-0.92=0.08α=1-0.90=0.1α2=0.05Z0.05=1.645
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A: Hi! Thank you for the question, As per the honor code, we are allowed to answer one question at a…
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A: Given information Error = 4% = 0.04 Confidence level = 0.95
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A: Given information- Margin of error, E = 6% = 0.06 Confidence level, c = 98% Since nothing is known…
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A: Sample size is 210. Percentage of successes is 70%. Percentage of confidence level is 90%.
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Q: Suppose you survey a random sample from a large population. How large must your sample be if you…
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A: (a)compute sample size ( n ) = n=(Z/E)^2*p*(1-p) Z a/2 at 0.1 level of significance is = 1.645sample…
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Q: ce interval for the mean is (44 ≤ μ ≤ 98), a) What is the point estimate?
A: a) The Point estimate can be calculated as: Point estimate=LowerLimit+UpperLimit2=44+982=71
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Q: The estimated prevalence is 25% and the desired confidence level is 95% with a margin of error of 4%…
A: The estimated prevalence =25% E= 4% CI =95% CI= 0.95 p= 0.25 E= 0.04
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A: Solution: 3. From the given information, confidence level is 0.90 and E=0.03.
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Q: If n=360 and ˆp(p-hat) =0.69, find the margin of error at a 95% confidence level
A:
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