i(t) L₁ m m m L3 L2 LA m -Ob L₁ = 20mH L2 = 50mH L3 = 70mH L4 = 65mH i(t) = 30mA.e Calculate the voltage drop across the equivalent inductance. vL (t) = = +3mV e (300 t) VI(t) = +900mV VI (t) = -900mV.e-(300) VI(t) = +900V.e - (300 .t) vL (t) = = −900 · e¯(300 .t) vL (t) = -900mV VI (t) = = +900 e -(300 .t) " VI(t) =-900V. e-(3 (300 .t) VL (t) = == -3mV e -(300 .t) VL (t) = +900mV. e-(300.t)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question

1.4

i(t)
L₁
m m
m
L3
L2
LA
m
-Ob
L₁
= 20mH
L2
= 50mH
L3
= 70mH
L4
= 65mH
i(t)
=
30mA.e
Transcribed Image Text:i(t) L₁ m m m L3 L2 LA m -Ob L₁ = 20mH L2 = 50mH L3 = 70mH L4 = 65mH i(t) = 30mA.e
Calculate the voltage drop across the equivalent inductance.
vL (t) =
= +3mV e
(300 t)
VI(t)
= +900mV
VI (t) = -900mV.e-(300)
VI(t)
= +900V.e
- (300 .t)
vL (t) =
= −900 · e¯(300 .t)
vL (t) = -900mV
VI (t) =
= +900 e
-(300 .t)
"
VI(t)
=-900V. e-(3
(300 .t)
VL (t) =
== -3mV e
-(300 .t)
VL (t) = +900mV. e-(300.t)
Transcribed Image Text:Calculate the voltage drop across the equivalent inductance. vL (t) = = +3mV e (300 t) VI(t) = +900mV VI (t) = -900mV.e-(300) VI(t) = +900V.e - (300 .t) vL (t) = = −900 · e¯(300 .t) vL (t) = -900mV VI (t) = = +900 e -(300 .t) " VI(t) =-900V. e-(3 (300 .t) VL (t) = == -3mV e -(300 .t) VL (t) = +900mV. e-(300.t)
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