ivative of p = 2xz nes maximum in t 3k

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 39RE
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Directional derivative of p = 2xz - y2, at the point
(1, 3, 2), becomes maximum in the direction of
1.
4i + 2j – 3k
4i — бј + 2k
3.
2i – 6j + 2k
4. 4i - бј - 2k
2.
Transcribed Image Text:Directional derivative of p = 2xz - y2, at the point (1, 3, 2), becomes maximum in the direction of 1. 4i + 2j – 3k 4i — бј + 2k 3. 2i – 6j + 2k 4. 4i - бј - 2k 2.
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