PYTHON: STACKS Given a balanced expression that can contain opening and closing parenthesis, check if it contains any duplicate parenthesis or not. If the expression contains duplicate parenthesis, the program outputs TRUE. Else, FALSE.Notes:o assume that the input expression is valido the expected average and worst complexity is O(1)Examples:Input: ((x+y))+zOutput: true1.Explanation: Duplicate () found in subexpression((x+y))Input: (x+y)2. Output: falseExplanation: No duplicate () is foundInput: ((x+y)+((z)))3. Output: trueExplanation: Duplicate () found in subexpression ((z))Hint:We can use a stack to solve this problem. The idea is to traverse the given expression and• If the current character in the expression is not a closing parenthesis ')', push the character into the stack.• If the current character in the expression is a closing parenthesis ')', check if the topmost element in the stack is an opening parenthesis or not. If it is an opening parenthesis, then the subexpression ending at the current character is of the form ((exp)); otherwise,continue popping characters from the stack till matching (' is found for current ')'.

Introduction : Stack is a data structure which follows LIFO (Last In First out) principle. We can…

iven a balanced expression that can contain opening and closing parenthesis, check if it contains any duplicate parenthesis or not. If the expression contains duplicate parenthesis, the program outputs TRUE. Else, FALSE.

iven a balanced expression that can contain opening and closing parenthesis, check if it contains any duplicate parenthesis or not. If the expression contains duplicate parenthesis, the program outputs TRUE. Else, FALSE.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Let n be a positive integer, and consider the following algorithm segment. for i := 1 to n for j := 1 to i [Statements in body of inner loop. None contain branching statements that lead outside the loop.] next j next i How many times will the inner loop be iterated when the algorithm is implemented and run?
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Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion/memoization. Make sure ALL test cases return expected outputs. Sample Input 04 412340123 Sample Output 013715 Explanation 0You are given the sequence 1,2,3,4.F0 = A0 = 1F1 = A1 + F0 = 2 + 1 = 3F2 = A2 + F1 + F0 = 3 + 3 + 1 = 7F3 = A3 + F2 + F1 + F0 = 4 + 7 + 3 + 1 = 15 The actual code def solve(k,a): MOD = 1000000007 # compute and return answer here q, n = list(map(int,input().rstrip().split(" ")))a = [int(input().rstrip()) for i in range(n)]outs = []for i in range(q): k = int(input().rstrip()) outs.append(solve(k,a))print("{}".format("\n".join(list(map(str,outs)))))
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Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Sample Input 0:5 20011014 Sample Output 0:1 1 Explanation 0:The best way to jump from square 1 to square 5 is by jumping 4 squares. That requires only 1 jump.In fact, that is the only solution, thus the second output is 1. Sample Input 1:6 3010100123 Sample Output 1:2 2 Explanation 1The best sequence is to jump 2 squares to square 3 then 3 squares to end in square 6.This is one solution. The other solution is to jump from 1 -> 3 -> 5 -> 6. These are the only two solutions, therefore the second output is 2. Sample Input 2:7 2000110037 Sample Output 2:-1 0 Explanation 2:It is impossible to reach square 7 with the specified jump values. The actual…
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consider a jewler who shows a collection of diamonds to a person. all diamonds have different integer ounce weights and are laid out in a single row on the table. what is the largest weight amount of diamonds that the person can take, provided that the person cannot select adjacent diamonds? use standard pseudocode notation similar to python to write a dynamic programming bottom up algorithm that solves this problem for any n number of diamonds.
Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply divide-and-conquer algorithm in the problem. Make sure all test cases return expected outputs by providing output screenshots. Provide screenshots Hint: Apply bisection method/modules Output FormatOutput contains a line with two space-separated integers W_a and W_b.- W_a is the maximum matchups won by Hamiltonia- W_b is the maximum matchups won by Burrgadia. Sample Input 03 554402410 Sample Output 03 0 Sample Input 15 4833485183 Sample Output 12 2 Sample Input 27 81028121912601319851 Sample Output 27 0 The actual code """Solves a test case Parameters:a : int - number of leaders in Hamiltoniab : int - number of leaders in Burrgadias_i : array-like - rap proficiencies of Hamiltonia's leadersr_j : array-like - rap proficiencies of…