ize P= 3z + 4y E to 21 + vS 16 27+ 3y S 24 z20, v 20
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- How would I go about solving ∭xzdV, where E is bounded by the planes z = 0, z=y, and the cylinder x2 + y2 = 1 in the half-space y ≥ 0 ? Thanks for you help. :)How would I solve ∭xzdV, where E is bounded by the planes z = 0, z=y, and the cylinder x2 + y2 = 1 in the half-space y ≥ 0 ? Any help would be greatly appreciated. :)Find the point on the planez = x + y + 1closest to the point P = (1, 0, 0). Hint: Minimize the square of thedistance.
- Find the maximum value that ƒ(x, y, z) = x2 + 2y - z2 can have on the line of intersection of the planes 2x - y = 0 and y + z = 0.Find the maximum value of w=xyz on the line of intersection of the two planes x+y+z=40 and x+y-z=0.The solid bounded by the surfaces S1: 2x + 3z = 6, S2: y = 2, S3: (y − 2) 2 = 2x − 2, S4: x = 0, S5: y = 0 and S6: z = 0, corresponds to: possible answers in the picture
- Find the minimum distance from the cone z = √(x2 + y2) to the point (-6, 4, 0).Find the dimensions of the rectangular box of maximum volume that has three of its faces in the coordinate planes, one vertex at the origin, and another vertex in the first octant on the plane 4x + 3y +z =12Use Lagrange multipliers to find the minimum distance from the plane x+y+z=5 to the point (5,4,4) . Round your answer to two decimal places if necessary.