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Izolasyon 1 k,= 0,08 W(m.K) 5= 12 cm Izolasyon 1 k,= 0,04 WI(m.K) 1=8 cm 5 cm -T,= Tavar 95 "C'de sivi The amount of heat that passes through the wall of a cylindrical pipe in the r-direction per unit time in bellrl conditions: Q = -kAT "() dT (r) T '() = dr. In the above expression, k is the heat transfer coefficient and A is the surface area. The surface of the pipe with inner diameter is covered with 3 cm Insulation 1 material and 4 cm isolation material as shown in the figure The heat conduction coefficients of insulation material 1 and 2 are ki = 0.04 W / mk and ka = 0.08 w/m-, respectively. The liquid flows through the pipe at 95 °C and the amount of heat lost (q /L, q = heat, L = length) from one meter of the pipe is 25.12 W /m In this case: a. Calculate the temperature shown as T: in the figure. b. Derive the equation showing the temperature change depending on the position along the insulation 2 (12 cm> r> 8 cm) and calculate the wall temperature (T2) using the equation.

Izolasyon 1 k,= 0,08 W(m.K) 5= 12 cm Izolasyon 1 k,= 0,04 WI(m.K) 1=8 cm 5 cm -T,= Tavar 95 "C'de sivi The amount of heat that passes through the wall of a cylindrical pipe in the r-direction per unit time in bellrl conditions: Q = -kAT "() dT (r) T '() = dr. In the above expression, k is the heat transfer coefficient and A is the surface area. The surface of the pipe with inner diameter is covered with 3 cm Insulation 1 material and 4 cm isolation material as shown in the figure The heat conduction coefficients of insulation material 1 and 2 are ki = 0.04 W / mk and ka = 0.08 w/m-, respectively. The liquid flows through the pipe at 95 °C and the amount of heat lost (q /L, q = heat, L = length) from one meter of the pipe is 25.12 W /m In this case: a. Calculate the temperature shown as T: in the figure. b. Derive the equation showing the temperature change depending on the position along the insulation 2 (12 cm> r> 8 cm) and calculate the wall temperature (T2) using the equation.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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izolasyon 1 k,= 0,08 WI(m.K) = 12 cm izolasyon 1 k,= 0,04 WI(m.K) 1,= 8 cm r,=5 cm T;= Tavar 95°C'de sivi The amount of heat that passes through the wall of a cylindrical pipe in the r-direction per unit time in bellrl conditions: Q = -kAT "() dT (r) T'() = dr. In the above expression, k is the heat transfer coefficient and A is the surface area. The surface of the pipe with inner diameter is covered with 3 cm Insulation 1 material and 4 cm isolation material as shown in the figure The heat conduction coefficients of insulation material 1 and 2 are ki = 0.04 W/ mK and ka = 0.08 W / m-, respectively. The liquid flows through the pipe at 95 °C and the amount of heat lost (q/L, q = heat, L= length) from one meter of the pipe is 25.12 W /m In this case: a. Calculate the temperature shown as T: in the figure. b. Derive the equation showing the temperature change depending on the position along the insulation 2 (12 cm> r> 8 cm) and calculate the wall temperature (T2) using the equation.
Transcribed Image Text:izolasyon 1 k,= 0,08 WI(m.K) = 12 cm izolasyon 1 k,= 0,04 WI(m.K) 1,= 8 cm r,=5 cm T;= Tavar 95°C'de sivi The amount of heat that passes through the wall of a cylindrical pipe in the r-direction per unit time in bellrl conditions: Q = -kAT "() dT (r) T'() = dr. In the above expression, k is the heat transfer coefficient and A is the surface area. The surface of the pipe with inner diameter is covered with 3 cm Insulation 1 material and 4 cm isolation material as shown in the figure The heat conduction coefficients of insulation material 1 and 2 are ki = 0.04 W/ mK and ka = 0.08 W / m-, respectively. The liquid flows through the pipe at 95 °C and the amount of heat lost (q/L, q = heat, L= length) from one meter of the pipe is 25.12 W /m In this case: a. Calculate the temperature shown as T: in the figure. b. Derive the equation showing the temperature change depending on the position along the insulation 2 (12 cm> r> 8 cm) and calculate the wall temperature (T2) using the equation.
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