Topic: Trigonometric and Hyperbolic funtions of complex numbersInstruction: Express your answer in rectangular form, 3 decimal places. Given:Za = -2 – 5iZp = 2.15 e4.18iZ. = 1.75 (cos165° + į sin165°)Za = 0.745/-36°Ze = 1+ 3iZf = 0.953 (cos324° + į sin324°)2.32/75°1.18 eni j. z = sinh (Z, – Zc) + cosh (zp – za)k. z = In [ tanh (z. – Za)]- Za)]

Use the following formulae, to obtain the solution. The polar form of the complex number z=x+iy is…

Answered: j. z= sinh (z, – Zc) + cosh (zħ – za)…

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j. z= sinh (z, – Zc) + cosh (zħ – za) k. z = In [ tanh (zc – Za)]

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.4: Multiple-angle Formulas

Problem 29E

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Question

Topic: Trigonometric and Hyperbolic funtions of complex numbers Instruction: Express your answer in rectangular form, 3 decimal places.

Given:
Za = -2 – 5i
Zp = 2.15 e4.18i
Z. = 1.75 (cos165° + į sin165°)
Za = 0.745/-36°
Ze = 1+ 3i
Zf = 0.953 (cos324° + į sin324°)
2.32/75°
1.18 eni

j. z = sinh (Z, – Zc) + cosh (zp – za)
k. z = In [ tanh (z. – Za)]
- Za)]

Combination of a real number and an imaginary number. They are numbers of the form a + b , where a and b are real numbers and i is an imaginary unit. Complex numbers are an extended idea of one-dimensional number line to two-dimensional complex plane.

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