J20JS2 JS2 52Q.22: For the magnetically coupled circuitshown, find the voltage across (-J10Q) 10:0ov52www.o10:90 Vimpedance and the total power?J102(Ans.:Vc=10.1523.96°v&Pr=17.3W)

Answered: Image /qna-images/answer/bb8ce3d9-c9d8-4903-a056-5819cadf700c.jpg

Answered: J20 52 J52 AJSO 552 100°V 10:90 V 102

Engineering

Electrical Engineering

J20 52 J52 AJSO 552 100°V 10:90 V 102

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

J20
JS2 JS2 52
Q.22: For the magnetically coupled circuit
shown, find the voltage across (-J10Q) 10:0ov
52
www.o
10:90 V
impedance and the total power?
J102
(Ans.:
Vc=10.1523.96°v
&
Pr=17.3W)

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