javacode will need to return the traversal of the nodes in DFS order, wherethe traversal starts from Node/Vertex 0.When you follow the traversal process as specified - the complexity of the solution will be linear as shown below.Time Complexity: O(V + E), where V is the number of Vertices andE is the number of Edges respectively.Space Complexity: O(V )The linear space complexity would come from the recursion (AKA ”recursionstack”) you employ to traverse the Graph. /* Class representing a directed graph using adjacency lists */static class Graphint V; //Number of VerticesLinkedList[] adj; // adjacency lists//ConstructorGraph(int V)this.V = V;adj = new LinkedList (V);for (int i = 0; i < adj.length; i++)adj [i] = new LinkedList();//To add an edge to graph2void addEdge (int v, int w)adj [v].add(w); // Add w to the list of v.The edges of the Graph is given to you.g. addEdge (0, 1);g. addEdge (0, 2);g. addEdge (2, 3);g. addEdge (2, 4);g. addEdge (4, 5);g. addEdge (1, 3);g. addEdge (3, 5); [1] With Recursion.1[2] Iteratively by using an explicit Stack.324Figure 1: Graph for Traversal

In depth traversal, we first investigate each node and its corresponding node, and you'll see that…

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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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java

code will need to return the traversal of the nodes in DFS order, where
the traversal starts from Node/Vertex 0.
When you follow the traversal process as specified - the complexity of the solution will be linear as shown below.
Time Complexity: O(V + E), where V is the number of Vertices and
E is the number of Edges respectively.
Space Complexity: O(V )
The linear space complexity would come from the recursion (AKA ”recursion
stack”) you employ to traverse the Graph.