Question

Asked Sep 13, 2019

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Jesse takes a 3-day kayak trip and travels 27 km south the city to a camp area. The trip to the camp with a 3 km/hour current takes 6 hours less time than the return against the current. Find the speed that Jesse travels in still water.

Step 1

Let, speed of Jesse in still water is v km/h.

Given that speed of current = 3 km/h

While going to the camp, Jesse travels with the current. So, her speed = (v+3) km/h

And, while returning from the camp, Jesse travels against the current. So, her speed = (v-3) km/h.

Step 2

Let, the time taken by Jesse while going to the camp = t hours

According to the question,

The time taken by Jesse while returning from the camp = (t+6) hours.

Step 3

Now we proceed fu...

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