Jse a trigonometric identity to find the indicated value in the specified quadrant. Function Value Quadrant Value cot 0 = -2 IV %3D sin 0 ep 1 Jse the trigonometric identity 1 + cot? 0 = csc² 0 and the information given in the problem to find csc2 0. csc? 0 = 5 %3D 5 ер 2 Use your result from Part 1 and the fact that the quadrant in question is Quadrant IV to determine csc 0. Csc e = -V5 -V5 | tep 3 Use a fundamental trigonometric identity to relate csc 0 and sin 0 to solve for sin 0. sin 0 =

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A: I am attaching image so that you understand each and every step.

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Q: See attachment

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