please answer immediatelyyy. thank youu JUX² +2x-8 dxEvaluatelx + 1Wx + 1)* + 9 = l(x + 1) + Vtx + 1}² – 9|]+c9ln(+ 1)/(x + 1)² – 9 – 3ln (x + 1) + /[x + 1)² – 9|+c(+ 1)/(x + 1)² – 9 – 9In (x + 1) + /[x + 1)² – 9|+cO None of the above

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Answered: JUX² +2x-8 dx Evaluate lx + 1Wx + 1)* +…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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We now need to attempt to find an exact value for n such that P(r ≥ 1) = 0.99. Clearly, if the bank has any chance of detecting a burglar they will need to have at least one alarm installed. So, we know that, minimally, n must be at least 1.Since n must be at least 1, suppose we start by trying n = 2, where there will be two alarms. When there are two alarms, r ≥ 1 means either one or both alarms could detect the burglar. If neither alarm detects the burglar it is considered a failure. Therefore, P(r ≥ 1) can be calculated using either of the following formulas. P(r ≥ 1) = P(1) + P(2) P(r ≥ 1) = 1 − P ( ___ ) fill in the blank
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I am trying to find out if the polynomial 12x^4+8x^3+9x^2+4x+4 is reducible or irreducible over Q. We can't apply Eisenstein's criterion here. But we can try this:12x^4+8x^3+9x^2+4x+4 = x^4+(2/3)x^3+(3/4)x^2+(1/3)x+(1/3) x^4+(2/3)x^3+(3/4)x^2+(1/3)x+(1/3)=(x^2+ax+b)(x^2+cx+d) = x^4+(a+c)x^3+(b+d+ac)x^2+(ad+dc)x+bd We get the equation system: a+c=(2/3)b+d+ac=(3/4)ab+bc=(1/3)bd=(1/3) I get the following result:b=(1/2)d=(2/3)c=(2+sqrt(19))/6 and (2-sqrt(19))/6a=(2/3)-((2+sqrt(19))/6) and (2/3)-((2-sqrt(19))/6) The expression in a contains an irrational number, sqrt(19), this means that the polynomial is irreversible over Q. Is this correct?

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JUX² +2x-8 dx Evaluate lx + 1Wx + 1)* + 9 = l(x + 1) + Vtx + 1}² – 9|]+c 9ln (+ 1)/(x + 1)² – 9 – 3ln (x + 1) + /[x + 1)² – 9|+c (+ 1)/(x + 1)² – 9 – 9In (x + 1) + /[x + 1)² – 9|+c O None of the above