2 theequality ofthe pair (5, 16). On its arrıval,the integers V1 and V2:V = 225 . 516 = 39 · 40 = 12 (mod 43)V2 = 313 = 12 (mod 43)PROBLEMS 10.3forwarded to a user with public key (47, 5, 10) and private key k(a) If the random integer chosen for encryption is j = 13, determine the cipher(b) Indicate how the ciphertext can be decrypted using the recipient's private ko2. Suppose that the following ciphertext is received by a person having ElGamal pukikey (71, 7, 32) and private key k = 30:19.%3D(56, 45) (56, 38) (56, 29) (56, 03) (56, 67)(56, 05) (56, 27) (56, 31) (56, 38) (56, 29)Obtain the plaintext message.3. The message NOT NOW (numerically 131419131422) is to be sent to a user of theElGamal system who has public key (37, 2, 18) and private key k = 17. If the integerj used to construct the ciphertext is changed over successive four-digit blocks fromj = 13 to j = 28 to j = 11, what is the encrypted message produced?4. Assume that a person has EIGamal public key (2633, 3, 1138) and private key k = 965.If the person selects the random interger j = 583 to encrypt the message BEWARE OFTHEM, obtain the resulting ciphertext.[Hint: 3583 = 1424 (mod 2633), 1138583 = 97 (mod 2633).]5. (a) A person with public key (31, 2, 22) and private key k = 17 wishes to sign a messagewhose first plaintext block is B = 14. If 13 is the integer chosen to construct thesignature, obtain the signature produced by the ElGamal algorithm.(b) Confirm the validity of this signature.%3D%3D%3Doliol

Answer of two we use descryption formula to find plain text:…

Answered: key (71, 7, 32) and private key k = 30:…

key (71, 7, 32) and private key k = 30: (56, 45) (56, 38) (56, 29) (56, 03) (56, 67) (56, 05) (56, 27) (56, 31) (56,38) (56, 29)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

the
equality of
the pair (5, 16). On its arrıval,
the integers V1 and V2:
V = 225 . 516 = 39 · 40 = 12 (mod 43)
V2 = 313 = 12 (mod 43)
PROBLEMS 10.3
forwarded to a user with public key (47, 5, 10) and private key k
(a) If the random integer chosen for encryption is j = 13, determine the cipher
(b) Indicate how the ciphertext can be decrypted using the recipient's private ko
2. Suppose that the following ciphertext is received by a person having ElGamal puki
key (71, 7, 32) and private key k = 30:
19.
%3D
(56, 45) (56, 38) (56, 29) (56, 03) (56, 67)
(56, 05) (56, 27) (56, 31) (56, 38) (56, 29)
Obtain the plaintext message.
3. The message NOT NOW (numerically 131419131422) is to be sent to a user of the
ElGamal system who has public key (37, 2, 18) and private key k = 17. If the integer
j used to construct the ciphertext is changed over successive four-digit blocks from
j = 13 to j = 28 to j = 11, what is the encrypted message produced?
4. Assume that a person has EIGamal public key (2633, 3, 1138) and private key k = 965.
If the person selects the random interger j = 583 to encrypt the message BEWARE OF
THEM, obtain the resulting ciphertext.
[Hint: 3583 = 1424 (mod 2633), 1138583 = 97 (mod 2633).]
5. (a) A person with public key (31, 2, 22) and private key k = 17 wishes to sign a message
whose first plaintext block is B = 14. If 13 is the integer chosen to construct the
signature, obtain the signature produced by the ElGamal algorithm.
(b) Confirm the validity of this signature.
%3D
%3D
%3D
oliol

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