l Verizon ? 10:53 PM 87% Done 3 of 3 Instructor-created question For y = 5-x, Osxs2 sketch the graph of the function, and then for the region below y = 5-x a) Sketch 4 circumscribed rectangles and find (Sa) overestimate b) Sketch 4 inscribed rectangles and find (S,) underestimate c) For positive integer "n" find (Sn) overest d) For positive integer "n" find (Sn) underest e) Find the area of the region by finding the limit: lim(S,) where S, is from part (c) or (d) |(5-x²) dx f) Check your answer by evaulating )+f( 1 )+f( )+f( 2 )] = units Ax = 2: S4) underestimate = Ax[f(5 c) For positive integer "n" find (Sn) overest Ax = ; For (S)overest k =a+ (k -1)Ax = 0+ (k - 1)- (in terms of k and n) 2 2 JAx in terms of k and n) S,Σ) ΔΣ15-(Κ- 1 in k= 1 п S, = x) Ax = 10 +( - 3 4 n(n - 1)(2n - 1) 4. =10- 2- n° k=1 d) For positive integer "n" find (Sn) underest 2 Ax = ; For (S)underest => C = a+kAx= 0 + k-: (in terms of k and n) s,- Σ ) Δκ Σ15-κ JAx; (in terms of k and n) k= 1 k=1 n(n + 1)(2n + 1) S = Y flcAy = 10 + 10- Question is complete. All parts showing !!

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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l Verizon ?
10:53 PM
87%
Done
3 of 3
Instructor-created question
For y = 5-x, Osxs2 sketch the graph of the function, and then for the region below y = 5-x
a) Sketch 4 circumscribed rectangles and find (Sa) overestimate
b) Sketch 4 inscribed rectangles and find (S,) underestimate
c) For positive integer "n" find (Sn) overest
d) For positive integer "n" find (Sn) underest
e) Find the area of the region by finding the limit: lim(S,) where S, is from part (c) or (d)
|(5-x²) dx
f) Check your answer by evaulating
)+f( 1 )+f(
)+f( 2 )] =
units
Ax =
2: S4) underestimate = Ax[f(5
c) For positive integer "n" find (Sn) overest
Ax =
; For (S)overest k =a+ (k -1)Ax = 0+ (k - 1)- (in terms of k and n)
2 2
JAx in terms of k and n)
S,Σ) ΔΣ15-(Κ- 1
in
k= 1
п
S, = x)
Ax = 10 +( -
3
4 n(n - 1)(2n - 1)
4.
=10-
2-
n°
k=1
d) For positive integer "n" find (Sn) underest
2
Ax =
; For (S)underest => C = a+kAx= 0 + k-: (in terms of k and n)
s,- Σ ) Δκ Σ15-κ
JAx; (in terms of k and n)
k= 1
k=1
n(n + 1)(2n + 1)
S = Y flcAy = 10 +
10-
Question is complete.
All parts showing
!!
Transcribed Image Text:l Verizon ? 10:53 PM 87% Done 3 of 3 Instructor-created question For y = 5-x, Osxs2 sketch the graph of the function, and then for the region below y = 5-x a) Sketch 4 circumscribed rectangles and find (Sa) overestimate b) Sketch 4 inscribed rectangles and find (S,) underestimate c) For positive integer "n" find (Sn) overest d) For positive integer "n" find (Sn) underest e) Find the area of the region by finding the limit: lim(S,) where S, is from part (c) or (d) |(5-x²) dx f) Check your answer by evaulating )+f( 1 )+f( )+f( 2 )] = units Ax = 2: S4) underestimate = Ax[f(5 c) For positive integer "n" find (Sn) overest Ax = ; For (S)overest k =a+ (k -1)Ax = 0+ (k - 1)- (in terms of k and n) 2 2 JAx in terms of k and n) S,Σ) ΔΣ15-(Κ- 1 in k= 1 п S, = x) Ax = 10 +( - 3 4 n(n - 1)(2n - 1) 4. =10- 2- n° k=1 d) For positive integer "n" find (Sn) underest 2 Ax = ; For (S)underest => C = a+kAx= 0 + k-: (in terms of k and n) s,- Σ ) Δκ Σ15-κ JAx; (in terms of k and n) k= 1 k=1 n(n + 1)(2n + 1) S = Y flcAy = 10 + 10- Question is complete. All parts showing !!
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