L{e_t (3 cos 6t 5 sin 6t)}
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- How did you get from 1+cos2x to 1+cos2x-sin2x? How did you get from 4cos(x/2) to -2(1+cosx)? How did you get from 1+cosx-since to 2cos2x?Does the tangent x cancel itself out? What does the last step say? I can’t read itFind all solutions of 4sin^2xtanx−tanx= 0 that are in the interval [0,2π)limx→0 (1−cos(5x))/(1−cos(9x))