Answer Learning Task 1, 2, and 3 Algebraic expressions are said to be similar if the expressions has thesame literal coefficients or variables, like 3x and x are similar while x and x2 areStnot.YcIn general, algebraic expressions are called polynomials. You can only per-ALform addition and subtraction to polynomials that are similar.as a letter that represents aIn the previous lesson you define variablesnumber. An expression can have a value if you replace the variable with a numberand perform the operations involved.The terms in the expression 3x + 5 are not similar, hence you cannot addthem. However if you give value to x, then you can perform the operations.2.Example:1. Find the value of 3x + 5, if x = 2Solution: 3x + 5 = 3(2) + 5 = 6 + 6 = 11.LMDThe value of the expression 3x + 5 is 11 when x = 2.2. Find the value of 6ab-C if a= 5; b = 3; c = 10abc6(5)(3) – 105(3)(10)Solution:6ab -c80abc15015Rules in Adding or Subtract PolynomialsStep 1. Arrange the polynomial in descending or ascending order if possible.Step 2. Group Terms which are similar.Step 3. Add/subtract the numerical coefficients, applying the rules in subtracțingand adding integers and copy the literal coefficients.Examples:1. Add: 4x2 - 2x +5 and 7+5x3 + 4x - x2DLearning Task 1: Find the value of the expression given the value of the variables1. Зх + 5; х%3D24. 3(xy + 6); x= -6 and y-12. 5xy + x- 4,x = -3 and y = 55. 2x +5 x = -3 and y = -83.6ab-c; a=5; b 3; c = 103x-yabcSUKAS Learning Task 2:A. Evaluate the algebraic expressionsapLet a = 4, b = -5, c 0.6, x = -3, y 0.4; z =Algebraic ExpressionbaValueexValueAlgebraic ExpressionII1. 3abc + bc - a6. 3x2 + 2xy - 3(ab)2th2. bxy + 5ab - ay7. 25 2x2y +3a2b- az23. abz - 8z +b8. (az)2 + 5x²y - 4bc9. 2x2y2-12abz164. ax + by - cz5. 4ax + cz10. 8z3-4x + y2B. Perform the indicated operationsSubtract:Add1. (5x - 3x2 + 4) + (6x3 - 4x2 - 7)6. (5x3 - 7x2 + 3x – 4) –(8x3 + 2x2 +3x - 7)2.-7x°y + 4x²y2 - 2 and 4x³y + 1-8x2y27. (2x2y - 5xy + 3y2) – (7xy – 6y² + 5x²y)3. (5+ 24y3- 7y²) + (-6y3 + 7y2 + 5)8. (9x5 - 6x³ + 7x²) – (7x³ – 6x5 + 2x²)4. (2x5-6x3 - 12x2 - 4) + (-11x5 + 8x + 2x2 + 6)9. Subtract 4x3 - 5x - 8 from 6x2 – 3x + 85. (3y3- 2y + y4 + 2y3 + 5) and (2y5 + 3y3 + 2+ 7) | 10. (1.5y³ + 4.8y2 + 12) - (y- 1.7y2 + 2y)Learning Task 3: Solve the following. Do this in a separate sheet of paper.1. A box is ( 2x-3) by ( x + 5) by ( 3x +1) , what is the volume of the box if x = 3cm?bhIf the base (b) = 10 cm and2. The formula for the area of a triangle is A=the height (h) = 6 cm, what is the area of the triangle?3. The length (1) of the rectangle is x2 + 2x - 3 and the width (w) is 5x + 4, whatis the perimeter of the rectangle.4. From the sum of 3x3 + 7x2 - 5 and 2x2 + 3x + 8 take away 5x2 + x -5.to mue srí5. What should be added to 3x3 + 4x2 -7 to have a sum of 4x3 + x2 + 5.

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Learning Task 1: Find the value of the expression given the value of the variables 1. 3x +5; x 2 4. 3(xy + 6); x -6 and y-1 2. 5xy + x - 4, x -3 and y = 5 5. 2x+5 x = -3 and y = -8 %3D 3. 6ab-c; a=5; b 3; c 10 3x-y abc