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- Q6. Write a function that takes an unsigned integer andreturns the number of '1' bits it has(also known as the Hamming weight).For example, the 32-bit integer '11' has binaryrepresentation 00000000000000000000000000001011,so the function should return 3.T(n)- O(k) : k is the number of 1s present in binary representation.NOTE: this complexity is better than O(log n).e.g. for n = 00010100000000000000000000000000only 2 iterations are required.Number of loops isequal to the number of 1s in the binary representation."""def count_ones_recur(n): Do it.Write a O(n) time complexity C-function void maxmin(int data[], int n, int *min, int *max); finds and returns max/largest and min/smallest element.1. Analyze the time complexity of the code segment and find their Big-O.void myfunction1(int n){for(int i=0; i < n; i++) {for(int j=0; j < n; j++) {for(int k=0; k < n; k++) {for(int m=0; m < n; m++) {printf("Hello!");} } } }}
- Dessssssssssinclude <bits/stdc++.h> using namespace std; int MSD(int n){ if(n == 0) return 0; int k = log10(n); int x = pow(10,k); int ans = n/x; return ans; } int main() { int n; cin >> n; cout << MSD(n).#include<stdio.h> #include<stdlib.h> main() { int m, sum = 0, counter = 0; int first = 2147483647, second = 2147483647, third = 2147483647, min = 2147483647; double average;printf("Enter an int or -1 to stop:\n"); while (1) {scanf_s("\n%d", &m);if (m == -1) { break; } sum = sum + m; counter++; if (m < first first == second first == third ) { third = second; second = first; first = m; } else if (m < second && m !=first ) { third = second; second = m; } else if (m < third && m != second) { third = m; } else if (first == second == third) { printf("min is: %d", first); }}printf("Sum of value: %d \n", sum); average =(double) sum /(double)counter; printf("Avarege is: %.2lf \n", average); printf("First min is: %d\n", first); printf("Second min is: %d\n", second); printf("Third min is: %d\n", third);system("pause"); } can you run this code pleaseEdit this program so that it returns ecg data instead of heart beat in BPM. #include <ArduinoBLE.h> #define BLE_UUID_HEART_RATE_SERVICE "180D"#define BLE_UUID_HEART_RATE_MEASURMENT "2A37"#define ECG_SERV_UUID 0x2D0D#define ECG_MEAS_UUID 0x2D37#define ECG_NUM_CHANS_UUID 0x2D38#define ECG_SAMPLE_SETS_UUID 0x2D39#define ECG_COMMAND_UUID 0x2D3A #define HRM_VALUE_FORMAT_8BIT 0#define HRM_VALUE_FORMAT_16BIT 1#define HRM_SENSOR_CONTACT_NOT_DETECTED ( 2 << 1 )#define HRM_SENSOR_CONTACT_DETECTED ( 3 << 1 ) typedef struct {uint8_t flags;uint8_t heartRate;} heart_rate_measurment_t; union heart_rate_measurment_u{struct {heart_rate_measurment_t values;};uint8_t bytes[ sizeof( heart_rate_measurment_t ) ];}; union heart_rate_measurment_u heartRate = { .values = { .flags = 0, .heartRate = 0 } }; #define BLE_DEVICE_NAME "Arduino HRM"#define BLE_LOCAL_NAME "Arduino HRM" BLEService heartRateService( BLE_UUID_HEART_RATE_SERVICE );BLECharacteristic heartRateCharacteristic(…
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- 5. (a) Calculate the total computing time of the following code fragment using O notation. void OrderedPairs(int arr[], int size) { for (int i = 0; i < size; i++) { for (int j = 0; j < size; j++) { printf("%d = %d\n", arr[i], arr[j]); } } } (b) Describe the order of growth for the function 5 log n + n + 3 using O notation.2._____'ccccc6 sloc) 497 Bytes Write a recursive function that returns the sum of the digits of a given integer.Input format :Integer NOutput format :Sum of digits of NConstraints :0 <= N <= 10^9Sample Input 1 :12345Sample Output 1 :15Sample Input 2 :9Sample Output 2 :9 Solution:///////////// public class solution { public static int sumOfDigits(int input){ int sum; if(input<10){ return input; } sum = (input % 10) + sumOfDigits(input / 10); return sum; }}..1. Write a C/C++ program that creates a table consisting of 500 randomly generated 3- tuple entries where each entry consists of processID, arrivalTime, and burstTime. The processID should be a “unique” 3-digit positive integer (e.g., 382, 881, 923, …). The arrivalTime should be an integer randomly picked from a range of values between 1 and 1,000. Note that the arrival times of two processes can be the same. The burstTime is an integer randomly picked from a range of values between 1 and 500. Your program should print out the table. An example output of your program would look something like this: processID arrivalTime burstTime 839 1 83 228 4 20 102 3 30 … 2. Using the code for Problem 1, write a C/C++ program that simulates execution of the Round Robin (RR) Algorithm with Time Quantum of 10 and calculates the average waiting time. Your program should run the RR algorithm 500 times. Note that each time you run the algorithm, a new table should be generated, and thus, the average…