Soil inciples-of-Foundation-Engineering-7th-Edition-SI-Units-ED.pdf - Adobe Acrobat Reader DCEdit View Window HelpTease mOVE thismeToolsLecture 5.pdfLecture 6.pdfPrinciples-of-Found... xSign In139 (159 of 815)100%3.3 Terzaghi's Bearing Capacity Theory139E Export PDFTable 3.1Aerzaghi's Bearing Capacity Factors Eqs. (3.4), (3.5), and (3.6) a FromKumbhojkar (1993)Adobe Export PDFN.NaN,N.N.N,5.701.000.002627.0914.219.84Convert PDF Files to Wordor Excel Online11.6013.7016.001.100.012729.2415.9017.8119.9822.4626.301.221.3528290.0431.6136.620.0634.2416.18Select PDF File46.971.490.103037.1619.13Principles-o.-Units-ED.pdtx31323357.341.640.1440.4125.2822.657.738.150,200.2728.5232.2326.8731.9461.8144.0472.0048.09Convert to8.609.0982.210.353452.6436.5038.0445.4154.362.440.443557.7541.44Microsoft Word (*.docx)109.612.690.563663.5347.16111210.1610.762.980.690.853770.0153.8061.5570.6165.27Document Language:10.763.293877.5078.61English (U.S.) Change1311.413.631.043985.9795.0312.1112.86144.021.264095.6681.27115.31414293.85108.75140.51171.99211.56154.451.524.925.456.04106.81119.67134.581.822.181613.684344126,50147.741714.60Convert15.1216.5617.692.593.073.6418151.95261.60172.28196.22196.7045173,28325.34407.11512.84207.4446204.198.269.19224.55258.282118.924.3147241.80Create PDF20.2721.7523.36225.0948287.85650.676.007,088.342310.2349298.71344.63831.992411.4050347.50415.141072.80Convert and edit PDFS2525.1312.72with Acrobat Pro DC*From Kumbhojkar (1993)Start Free Trial Refer to the following figure, Find the dimension of the rectangular footingrequired to support 680 KN/m using Terzaghi equation? Assume general shearfailure will occur, L=1.35 B, and F.S=4.0680 KN/m//////Ya =14.7kN/m?1.8 mBxL0 = 26°C = 15 kN/m?Ya= 18 kN/m?

Data given:Load = 680kN/mdepth of footing (Df) =1.8mγd=14.7kN/m3ϕ=260C=15kN/m2F.S =4.0For…

Lecture 6.pdf 139 (159 of 815) 012345678 Principles-of-Found.... N₂ 5.70 6.00 6.30 6.62 6.97 7.34 7.73 8.15 8.60 Table 3.1 erzaghi's Bearing Capacity Factors Eqs. (3,4), (3.5), and (3.6) a From Kumbhojkar (1993) N₂ 1.00 1.10 1.22 1.35 1.49 1.64 1.81 2.00 2.21 N," 0.00 0.01 0.04 0.06 0.10 0.14 100% 0.20 0.27 0.35 3.3 Terzaghi's Bearing Capacity Theory 139 $ 26 27 28 29 30 31 32 33 34 N₂ 27.09 29.24 31.61 34.24 37.16 40.41 44.04 48.09 52.64 N₂ 14.21 15.90 17.81 19.98 EXTE 22.46 25.28 28.52 32.23 36.50 N₂ 9.84 11.60 13.70 16.18 19.13 22.65 26.87 31.94 38.04

Lecture 6.pdf 139 (159 of 815) 012345678 Principles-of-Found.... N₂ 5.70 6.00 6.30 6.62 6.97 7.34 7.73 8.15 8.60 Table 3.1 erzaghi's Bearing Capacity Factors Eqs. (3,4), (3.5), and (3.6) a From Kumbhojkar (1993) N₂ 1.00 1.10 1.22 1.35 1.49 1.64 1.81 2.00 2.21 N," 0.00 0.01 0.04 0.06 0.10 0.14 100% 0.20 0.27 0.35 3.3 Terzaghi's Bearing Capacity Theory 139 $ 26 27 28 29 30 31 32 33 34 N₂ 27.09 29.24 31.61 34.24 37.16 40.41 44.04 48.09 52.64 N₂ 14.21 15.90 17.81 19.98 EXTE 22.46 25.28 28.52 32.23 36.50 N₂ 9.84 11.60 13.70 16.18 19.13 22.65 26.87 31.94 38.04

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter16: Soil Bearing Capacity For Shallow Foundations

Section: Chapter Questions

Problem 16.2P: Refer to Problem 16.1. If a square footing with dimension 2 m 2 m is used instead of the wall...

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Refer to Problem 16.1. If a square footing with dimension 2 m 2 m is used instead of the wall footing, what would be the allowable bearing capacity? 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17
Redo Problem 16.2 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17 6.2 Refer to Problem 16.1. If a square footing with dimension 2 m 2 m is used instead of the wall footing, what would be the allowable bearing capacity?
Redo Problem 16.1 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17
A 5.0 ft wide square footing is placed at 3.0 ft depth within the ground where c = 200 lb/ft2, = 25, and = 115.0 lb/ft3. Determine the ultimate bearing capacity of the footing using Terzaghis bearing capacity equation and the bearing capacity factors from Table 6.1. What is the maximum column load that can be allowed with a factor of safety of 3.0?
Redo Problem 16.13 with the following data: gross allowable load = 184,000 lb, = 121 lb/ft3, c = 0, =26, Df = 6.5 ft., and required factor of safety = 2.5. 16.13 A square footing (B B) must carry a gross allowable load of 1160 kN. The base of the footing is to be located at a depth of 2 m below the ground surface. If the required factor of safety is 4.5, determine the size of the footing. Use Terzaghis bearing capacity factors and assume general shear failure of soil. Given: = 17 kN/m3, c = 48 kN/m2, =31.
A square footing has the following properties. The footing will carry a gross load of 60,000lb. Using factor of safety of 3.0, determine the size of the footing. (answer3.25’)Given: ∂ = 110 pcf Df = 2ftc = 0 B = 3.0 ftØ = 350 FS = 4.0
A square footing having a dimension of 3.5m is supported by a soil with the following properties: ø = 17 degrees c = 45 kPa y1 = 17 kN/m3 Ysat = 20 kN/m3 The bottom of the footing is 1.9m below the ground surface. Use FS = 3 and Ywy w = 9.81 kN/m3. Using the general capacity equation or Meyerhof's Equation, If GWT is at the bottom of the footing, determine the gross allowable bearing capacity (in kPa). If the GWT is found 1m below ground surface, what is the gross allowable bearing capacity (in kPa)? If the GWT is found 4 m below ground surface, what is the gross allowable bearing capacity (in kPa)?
A rectangular footing has dimensions shown and is acted upon by a dead load of 1200 kN and a live load of 1600 kN. The column dimensions is 300x600 where the shorter dimension is parallel to B. The thickness of the footing is 500mm. f'c = 28 MPa and fy = 420 MPa for diameter 20mm bars. A = 2.4m and B = 4.2m Calculate the Following: A.) Critical Ultimate Shear Strength and Shear Force of the footing for beam shear action, kNB.) Critical wide beam nominal shear stress, MPaC.) Ultimate Shear Strength of the footing in punching shear action, kN Please answer it ASAP and correctly for upvotes.
A square footing is shown below. The footing will carry a gross load of 700 kN. Using a factor of safety 3, determine the required value of B. Assume general shear failure. ?? = ??. ?? , ?? = ??. ??, ?? = ??. ?�
A rectangular footing has dimensions shown and is acted upon by a dead load of 653 KN and a live load of 647 kN. The column dimension is 269x677 mm where the shorter dimension is parallel to B. The thickness of the footing is 442mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=2.9m and B=4.8m Calculate the ratio of the Ultimate Shear Force to Shear Capacity in one-way shear. Consider critical case only.
A circular footing having a diameter of 1.2 m. has its bottom at a depth of 2.6 m. from the ground surface. The water table is located at a depth of 1.2 m. below the ground. The soil has the following properties: γd = 18.26 kN/m3, γsat = 19.10 kN/m3, c = 15.18 kPa, Nc = 35.06, Nq = 22.03, Nγ = 19.01. Determine the allowable load, in kN, that the footing can carry using factor of safety of 2.7
A rectangular footing (base = 5.62m., length = 1.78 m.) has its bottom 3.05 m. below the ground surface. Unit weight of soil is 18.23 kN/m3, unconfined compressive strength = 164 kPa. Use angle of internal friction = 10° (Nc = 9, Nq = 5.6, = 2.1). Compute the allowable load (in kN) that the footing could carry. Use FS = 2. Use stored value. Answer in 5 decimal places.