length of the curve x = (y + 2)/2 from y-0 to y-1 1. Find the arc

Q: Find the arc length of the graph of the function over the indicated interval. 3/2 + 1 y = y 6 4 -1 1…

A: y=23x2+132 Differentiating with respect to x, we get dydx=23·32x2+132-1·dx2+1dx=x2+112·2x=2xx2+112

Q: y = + 2. Find the arc length of the curve from x=2 to x-3

A: Since you have asked multiple questions but according to our company's guidelines I can only answer…

Q: Find the arc length of the graph of the function over the indicated interval. 3/2 + 1 2 y = x2 3 y 4…

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Q: Find the arc length of the function y = x2 + x - 2  on the interval [-2,1].

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Q: What is the arc length of the curve y = (2/3)(x-4)3/2 from the point where x = 4 to the point where…

A: Given: y=23(x-4)32

Q: Find the exact arc length of the curve over the stated interval. y = 7x3/2 – 2, from x = 0 to x = 1…

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Q: Find the arc length of the graph of y = ln(sin x) from x = π /4 to x = π/2.

A: The formula to find arc length of a curve f(x) from x=a to x=b is, L=∫ab1+f'(x)2dx.

Q: Find the arc length of y=((x^3)/6) + (1/(2x)) with the interval of [(1/2), 1].

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Q: Find the exact arc length of the curve over the stated interval. y = 8x2/3, from x = 1 to x = 8 %3D…

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Q: Find the length of the arc of the curve  where y=x^2+1 from the point  where y=1 to the point…

A: Formula to find the required arc length. Formula to find the arc length for the limits of y is…

Q: Find the arc length of the graph of y == 6 2x on the interval 2 L2

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Q: Find the exact arc length of the curve over the stated interval. y = 7x2/3, from x = 1 to x = 8…

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Q: Find the exact arc length of the curve over the stated interval. y = 8x2/3, from x = 1 to x = 8…

A: The expression for the arc length of the curve is: L=∫x1x21+dydx2dx   Given; y=8x23x1=1 & x2=8

Q: Find the arc length in the second quadrant of the curve x23 +y2/3 = 25 from x = - 125 to x = – 8.…

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Q: Find the arc length of the curve y=ln (secx) from x=0 to x=(pi )/(3)

A: Use formula

Q: Find the exact arc length of the curve over the stated interval. Y = 5x³/2 2. from x = 0 to x = 1…

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Q: Find the exact arc length of the curve over the stated interval. y = 9x³/25, from x = 0 to x = 1…

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Q: Find the arc length of the curvex (y² + 2)3/2 from y-0 to y=1

A: As per the company guidelines we can solve first question. I hope that the given solution will help…

Q: Find the exact arc length of the curve over the stated interval. y = 9x/2 - 4, from a = 0 to x = 1…

A: y=9x32-4To find the arc length from x=0 to x=1

Q: Find the length of arc of the curve 6xy = x* + 3, from the point where x = 1 to the point where x =…

A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: Find the arc length function for the curve y=  sin inverse x  + sqrt ( 1 - x sq. ) with starting…

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Q: Find the exact arc length of the curve. x6 + 8 y = from x = 1 to x = 3. 16x2 Give the exact answer…

A: To Determine: find the exact arc length of the curve  Given: we have a function y=x6+816x2…

Q: Find the length of the arc of x²+y²=64 from x=-1 to x=-3, in the second quadrant.

A: Given curve: x2+y2=64

Q: Find the arc length of the graph of the function over the indicated interval. x2 3/2 + 1 y = y 4 1 3…

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Q: Find the arc-length of the curve y = 2x2 +3,0 <x < 1.

A: We can find the arc length as below

Q: Find the arc length function for the curve y = 2x/2 with starting point Po(25, 250). s(x) =

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Q: Find the arc length of the graph of the function over the indicated interval. x= =cy² + 2)3/2, 0sys2

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Q: Find the length of arc of the curve 6xy = x^4 + 3, from the point where x=1 to the point where x=2

A: The given curve is: 6xy=x4+3 y=x46x+36xy=x36+12x Differentiate it: dydx=3x26-12x2dydx=x22-12x2

Q: Find the arc length of y^3 +y= x^2+6x on the interval [-5, -1]

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Q: Find the length of the arc of the curve y=x+3 from the point where y=2 to the point where y=x^2+1…

A: y=x+3  ⇒x=y-3⇒dx=dy⇒dxdy=1 The formula for the length of the arc from the point y=2 to y=x2+1…

Q: Find the arc length of the curve y= 7x+4 On the interval 3

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Q: Find the exact arc length of the curve over the stated interval. y = 3x3/2 – 4, from x = 0 to x = 1…

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Q: Find the arc length in the second quadrant of the curve x23 + y23 2/3 = 9 from x = - 27 to x = – 1.…

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Q: Find the length of arc of the curve y =÷(x² + 2)3/2 from the point where x = 0 to the point where x…

A: Consider the given curve: fx=13x2+232Interval  0≤x≤3Differentiate w.r.t.…

Q: Find the arc length of y³+y=x²+6x on the interval [-5,-1].

A: Solution:   Given that,      y3+y=x2+6x,  interval -5, -1         Then, differentiating with…

Q: Find the exact arc length of the curve over the stated interval. y = 7x%/2 – 2, from x = 0 to x = 1…

A: Here we have to find the arc length of the curve y=7x32-2 from x=0 to x=1

Q: 3 The arc length of the portion of the curve y=x 2 with 0<x<4 is

A: I have append the formula used to find arc length in the solution part.

Q: Find the arc length of the curve y=(1/8)(x^2−8ln(x)) from x=3 to x=8

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Q: Find the exact arc length of the curve over the stated interval. y = 9x3/2 – 4, from x = 0 to x = 1…

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Q: Find the exact arc length of the curve over the stated interval. y = 5x3/2 – 5, from x = 0 to x = 1…

A: Explained below

Q: ind the length of arc of the curve 6xy = x⁴ + 3, from the point where x = 1 to the point where x =…

A: Here given equation as 6xy=x4+3ory=16x3+3x Differentiate with respect to x…

Q: from x-2 to x-3 2. Find the arc length of the curve y = 16

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Q: x3 (b) Calculate the arc length of the curve y = 12 from x = 1 and x = 2. %3D

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Q: he length of the curve y = sin(3X) from x = 0 to I= is given by

A:

Q: Find the arc length of the curves x = e-20 (sine + cos0), y = e-20 (sine – cose) over the interval…

A: Definition used -                    Length of the curve…

Q: 3. Find the arc length of the curve æ = 5 + y3/2 between y = 0 and y = 2.

A:

Q: Find the exact arc length of the curve over the stated interval. y = 8x2/3, from x = 1 to x = 8 %3D…

A: The curve is y=8x2/3

Q: 4. Find the arc length of the curve x= - y* + ÷y¯² from y=1 to y=4

A: We have to find the arc length from the given condition

Q: Find the exact length of the curve x3 y = 6. 1 <x < 1. 2x Arc length

A: we have to find the arc length of the given curve

Q: Find the exact arc length of the curve over the stated interval. y = 7x3/2 – 3, from x = 0 to x = 1…

A: Given curve is y=7x3/2-3 ,[0,1]

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.