Length of wire: 0.240 m Cross Sectional Diameter Voltage (V) Current Resistance Resistivity Area (m) (A) ( ) 0.000511 0.0901 1.08790 0.000813 0.0363 1.09656 0.001025 0.0231 111482 0.001277 0.0147 1.10209 Mean of Resistivity: Standard Deviation of Resistivity:
Length of wire: 0.240 m Cross Sectional Diameter Voltage (V) Current Resistance Resistivity Area (m) (A) ( ) 0.000511 0.0901 1.08790 0.000813 0.0363 1.09656 0.001025 0.0231 111482 0.001277 0.0147 1.10209 Mean of Resistivity: Standard Deviation of Resistivity:
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If you're going to answer only one question, then just answer the standard deviation of resistivity. But I'd appreciate it if u do everything thanks.
Transcribed Image Text:NAME:
DATE:
Table 2 - Resistivity vs Diameter
Length of wire: 0,240 m
Cross Sectional
Diameter
Voltage
Curent
Resistance
Resistivity
Area
(m)
(V)
(A)
( )
0.000511
0.0901
1.08790
0.000813
0.0363
1.09656
0.001025
0.0231
1.11482
0.001277
0.0147
1.10209
Mean of Resistivity
Standard Deviation of Resistivity.
Theoretical Resistivity ,
Percent Error.
Transcribed Image Text:Discussion:
Ohm's Law describes the relationship between the resistance (R) of a wire, the voltage drop across it (V), and current
through it (D):
V = RI
(1)
Applying a known current to a wire and measuring the voltage across it will let you determine the resistance of the
wire by solving equation 1:
R=
(2)
The resistance of a particular element depends on its geometry, the resistivity and the temperature. Resistivity is the
tendency of the material to behave as a resistor and is an inherent property of a material, in the same sense that density or
thermal expansion are inherent properties. Materials with lower resistivity, like copper, are good conductors of electricity
and widely used in circuit components while those with larger resistivity, like rubber, are used as insulators.
For a wire with length (L), eross-sectional area (A), and made from a material with resistivity (p) the resistance (R)
will be given by the following equation:
R=L
(3)
In case that the geometry (length and cross sectional area) and the resistance of the wire is known, then is possible to
caleulate the resistivity solving equation 3:
(4)
A wire can be consider as a long eylinder; then the cross sectional area would have a circular shape
as shonn in
Figure 2.
Cross Sectional
Area
Length
Figure 2
Then the cross sectional area of the wire can be caleulated using the equation of the area of a circle:
A = mr
(5)
In this experiment, you will measure V and I to determine R for various lengths of wire. You will then make a graph
of Resistance (Y-axis) versus length (X-axis). The plot will result in a straight line that has a slope equal to
slope =A
(6)
From equation 6, it is possible to solve the resistivity in terms of the slope and the cross sectional area:
p= elope + A
(7)
The manufacture values of the resistivity corresponding to the wires used in the experiment are reported in Table 1.
These values will be used as the theoretical when caleulating percent error.
Table 1. Theoretical resistivity of different materials according to manufacturer.
Attracted
Material
Color
Diameter (m)
Resistivity (Qm)
to Magnet
Brass
Yellow
0.000508
7.0 x10
No
0.000813
0.001016
0.001270
Copper
Nicbrome
Red
No
0.001016
1.8 x10
Dark Gray No
Dark Gray Yes
0.001016
105 x10
Stainless
0.001016
79 x10
Steal
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