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Let A = {a, b, c, d}and B = {r, s, t} Determine whether each of the following functions is one-to-one or onto. f: A B f(a) = t, f(b) = r, f(c) = t, f(d) f: A B f(a) = t, f(b) = r, f(c) = t, f(d) = = S = r f: B→ A f(r) = c, f(s) = d, f(t) = a f: BA f(r) = b, f(s) = c, f(t) = b 1. f: A→ A f(a) = d, f(b) = a, f(c) = b, f(d) = c 3. 2. 4. Neither one-to- one nor onto One-to- one but not onto Onto but not one- to-one Both one-to- one and onto

Let A = {a, b, c, d}and B = {r, s, t} Determine whether each of the following functions is one-to-one or onto. f: A B f(a) = t, f(b) = r, f(c) = t, f(d) f: A B f(a) = t, f(b) = r, f(c) = t, f(d) = = S = r f: B→ A f(r) = c, f(s) = d, f(t) = a f: BA f(r) = b, f(s) = c, f(t) = b 1. f: A→ A f(a) = d, f(b) = a, f(c) = b, f(d) = c 3. 2. 4. Neither one-to- one nor onto One-to- one but not onto Onto but not one- to-one Both one-to- one and onto

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 51E
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Let A = {a, b, c, d}and B = {r, s, t} Determine whether each of the following functions is one-to-one or onto. f: A B f(a) = t, f(b) = r, f(c) = t, f(d) = r f: A B f(a) = t, f(b) = r, f(c) = t, f(d): f: B→ A f(r) = = c, f(s) = d, f(t) = a = f: B→ A f(r) = b, f(s) = c, f(t) = b S 1. 2. Neither one-to- f: A → A f(a) = d, f(b) = a, f(c) = b, f(d) = c 3. Onto but not one- to-one 4. one nor onto One-to- one but not onto Both one-to- one and onto
Transcribed Image Text:Let A = {a, b, c, d}and B = {r, s, t} Determine whether each of the following functions is one-to-one or onto. f: A B f(a) = t, f(b) = r, f(c) = t, f(d) = r f: A B f(a) = t, f(b) = r, f(c) = t, f(d): f: B→ A f(r) = = c, f(s) = d, f(t) = a = f: B→ A f(r) = b, f(s) = c, f(t) = b S 1. 2. Neither one-to- f: A → A f(a) = d, f(b) = a, f(c) = b, f(d) = c 3. Onto but not one- to-one 4. one nor onto One-to- one but not onto Both one-to- one and onto
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