Let A be the area of the region that lies under the graph g(x)=sin() between x=0 and x=2. Using right-han endpoints, an expression for A as a limit is the following O A= lim 1 sin) n- co n j=1 O A= lim n- co n sin sin 6n A= lim n- 00 n i=1 n O A= lim -25 n- 00 cos 3n j=1 n- co n i=1 3n n-1 A= lim 2 n- 0o n i=0 sin O A= lim 2 n- co n i=0 sin 3n O A= lim n- 00 cos 3n in i=1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.6: Permutations
Problem 47E
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Let A be the area of the region that lies under the graph g(x)=sin() between x=0 and x=2. Using right-hand
endpoints, an expression for A as a limit is the following
O A= lim 1 sin)
n- 00 n
O A= lim
n- 0o n
sin
sin
6n
A= lim
n- 0o n
i=1
n
O A= lim -2S
cos
3n
n- 00
i=1
3n
n- co n
i=1
n-1
A= lim 2
n- 00 n
j=0
sin)
O A= lim
2
sin
3n
n- 00 n
j=0
A= lim
cos
3n
in
i=1
n- 00
Transcribed Image Text:Let A be the area of the region that lies under the graph g(x)=sin() between x=0 and x=2. Using right-hand endpoints, an expression for A as a limit is the following O A= lim 1 sin) n- 00 n O A= lim n- 0o n sin sin 6n A= lim n- 0o n i=1 n O A= lim -2S cos 3n n- 00 i=1 3n n- co n i=1 n-1 A= lim 2 n- 00 n j=0 sin) O A= lim 2 sin 3n n- 00 n j=0 A= lim cos 3n in i=1 n- 00
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