Let B = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows R = {(0, 1), (1,1), (2, 3),(3,3)} S= {(0, 0), (0, 2), (0, 3), (2, 3)}, T = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (1, 3),(2, 2), (3, 0), (3, 3)}, T has . properties Seç. The equivalance relation is: Seç..

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter5: Rings, Integral Domains, And Fields
Section5.4: Ordered Integral Domains
Problem 1E: Complete the proof of Theorem 5.30 by providing the following statements, where and are arbitrary...
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Let B = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows:
R = {(0, 1), (1,1), (2, 3),(3,3)}
S= {(0, 0), (0, 2), (0, 3), (2, 3)},
T = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (1, 3),(2, 2), (3, 0), (3, 3)},
%3D
T has . properties
Seç.
Seç.
The equivalance relation is:
R
S has . properties
transitive, symmetric but not reflexive
reflexive, symmetric but not transitive
R has . properties
reflexive, symmetric and transitive
reflexive, but neither symmetric nor transitive
reflexive, transitive but not symmetric
transitive, but neither symmetric nor reflexive
symmetric, but neither reflexive nor transitive
Transcribed Image Text:Let B = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows: R = {(0, 1), (1,1), (2, 3),(3,3)} S= {(0, 0), (0, 2), (0, 3), (2, 3)}, T = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (1, 3),(2, 2), (3, 0), (3, 3)}, %3D T has . properties Seç. Seç. The equivalance relation is: R S has . properties transitive, symmetric but not reflexive reflexive, symmetric but not transitive R has . properties reflexive, symmetric and transitive reflexive, but neither symmetric nor transitive reflexive, transitive but not symmetric transitive, but neither symmetric nor reflexive symmetric, but neither reflexive nor transitive
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