let be Solve 1G:= {(x, y) ЄR² = (0,2), y = (0, 2)}" Ω:= = {(x, y, z) = R³ : x = (0, 2), y Є (0,2), z Є (0, 1)} = G × (0, 1) . du(x, y, z) = 0 (Au(x, y, z) = 0 V(x,y,z) ΕΩ V(x, y) Є OG x (0, 1) (x, y, 0) = 0 V(x, y) Є G ди მა (x, y, 1) = cos (πx) + cos (лy) +7 cos (2πx) cos (TV) V(x, y) = G.

let be Solve 1G:= {(x, y) ЄR² = (0,2), y = (0, 2)}" Ω:= = {(x, y, z) = R³ : x = (0, 2), y Є (0,2), z Є (0, 1)} = G × (0, 1) . du(x, y, z) = 0 (Au(x, y, z) = 0 V(x,y,z) ΕΩ V(x, y) Є OG x (0, 1) (x, y, 0) = 0 V(x, y) Є G ди მა (x, y, 1) = cos (πx) + cos (лy) +7 cos (2πx) cos (TV) V(x, y) = G.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section9.7: The Inverse Of A Matrix

Problem 31E

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