Let d be the distance from a point on the plane x - 2y + 3z = 9 to the point (0, 2, 1). For f(x, y) = d², find the following derivatives. fy(X, v) = 2х — 3 2 ( 2y – x +1 4 2у — х 2y – 2+ 3 3 Find the critical point. (х, у) %-

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Chapter1: Functions And Models
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Let d be the distance from a point on the plane x – 2y + 3z = 9 to the point (0, 2, 1). For f(x, y) = d², find the following derivatives.
2y -
fy(x, y)
2x
+ 1
4
2y
y(x, y)
2у — 2 +
3
- x
+1
3
Find the critical point.
(х, у) %3D
Find the point on the plane x - 2y + 3z = 9 that is closest to the point (0, 2, 1).
(х, у, 2) %3D
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Transcribed Image Text:Let d be the distance from a point on the plane x – 2y + 3z = 9 to the point (0, 2, 1). For f(x, y) = d², find the following derivatives. 2y - fy(x, y) 2x + 1 4 2y y(x, y) 2у — 2 + 3 - x +1 3 Find the critical point. (х, у) %3D Find the point on the plane x - 2y + 3z = 9 that is closest to the point (0, 2, 1). (х, у, 2) %3D Need Help? Read It
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