Let E = {n E Z|n is even} and let O = {n E Z|n is odd}. Define a function f: E × O + Z by f(x, y) = x + y. The the function f is one to one only onto only one to one correspondence O neither one to one nor onto

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A: here we can use contradiction to prove this stetements.

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A: Let, x=2 that is x is even. Then, fx=x2+2 So, f2=22+2=6f-2=-22+2=6 Therefore, f2=f-2 Then, the given…

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