Let f be a mapping from ]0,1[ to ]0, 1[defined by f(x) = x². Then *O If(x)-f(y)|<2|x-y| and f has no fixed point.f has a unique fixed pointO If(x)-f(y)|<2|x-y| and f has a fixed point.O None of the choices.

A function f(x) is said to have a fixed point if there exists an x in domain such that .

Let f be a mapping from ]0,1[ to ]0, 1[ defined by f(x) = x². Then * O If(x)-f(y)|<2|x-y| and f has no fixed point. O f has a unique fixed point |f(x)-f(y)|s2|x-y| and f has a fixed point. None of the choices.

Let f be a mapping from ]0,1[ to ]0, 1[ defined by f(x) = x². Then * O If(x)-f(y)|<2|x-y| and f has no fixed point. O f has a unique fixed point |f(x)-f(y)|s2|x-y| and f has a fixed point. None of the choices.

Elements Of Modern Algebra

8th Edition

ISBN:9781285463230

Author:Gilbert, Linda, Jimmie

Publisher:Gilbert, Linda, Jimmie

Chapter1: Fundamentals

Section1.5: Permutations And Inverses

Problem 10E: 10. Let and be mappings from to. Prove that if is invertible, then is onto and is...

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Question

Let f be a mapping from ]0,1[ to ]0, 1[
defined by f(x) = x². Then *
O If(x)-f(y)|<2|x-y| and f has no fixed point.
f has a unique fixed point
O If(x)-f(y)|<2|x-y| and f has a fixed point.
O None of the choices.

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