Let f(v) be the gas consumption in liters/km of a car traveling at velocity v km/hr. In addition, you know that f(60) = 0.05 and f'(60) = 0.0005 (a) Let g(v) be the distance in km that the car goes on one liter of gas at velocity v. What is the relationship between g(v) and f(v)? g(v) = f(v) O g(v) = (v) Og(v) = v.f(v) f(v) V g(v) = O g(v) = Find g'(60). V f(v) (b) Let h(v) be the liters of gas the car uses in one hour at velocity v. What is the relationship between h(v) and f(v)? Oh(v) = f(v) ○ h(v) = f(v) Oh(v) = Oh(v) = v.f(v) Oh(v) = 1 f(v) V V f(v) Find h'(60).
Let f(v) be the gas consumption in liters/km of a car traveling at velocity v km/hr. In addition, you know that f(60) = 0.05 and f'(60) = 0.0005 (a) Let g(v) be the distance in km that the car goes on one liter of gas at velocity v. What is the relationship between g(v) and f(v)? g(v) = f(v) O g(v) = (v) Og(v) = v.f(v) f(v) V g(v) = O g(v) = Find g'(60). V f(v) (b) Let h(v) be the liters of gas the car uses in one hour at velocity v. What is the relationship between h(v) and f(v)? Oh(v) = f(v) ○ h(v) = f(v) Oh(v) = Oh(v) = v.f(v) Oh(v) = 1 f(v) V V f(v) Find h'(60).
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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