Let f(x) = (x - 3)-2. Find all values of c in (1, 7) such that f(7) – f(1) = f'(c)(7 – 1). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)с 3Based off of this information, what conclusions can be made about the Mean Value Theorem?f(7) – f(1)This contradicts the Mean Value Theorem since f satisfies the hypotheses on the given interval but there does not exist any c on (1, 7) such that f'(c)7 - 1This does not contradict the Mean Value Theorem since f is not continuous at x = 3.f(7) – f(1)This does not contradict the Mean Value Theorem since f is continuous on (1, 7), and there exists a c on (1, 7) such that f '(c)7 – 1F(7) – f(1)This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f'(c) =but f is not continuous at x = 3.7 - 1Nothing can be concluded.

Mean Value Theorem : Suppose f(x) is a function that satisfy the following properties :1. f(x) is…

Let f(x) = (x - 3)-2. Find all values of c in (1, 7) such that f(7) - f(1) = f'(c)(7 - 1). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) C = Based off of this information, what conclusions can be made about the Mean Value Theorem? f(7) – f(1) 7 - 1 This contradicts the Mean Value Theorem since f satisfies the hypotheses on the given interval but there does not exist any c on (1, 7) such that f'(c) = This does not contradict the Mean Value Theorem since f is not continuous at x = 3. f(7) – f(1) This does not contradict the Mean Value Theorem since f is continuous on (1, 7), and there exists a c on (1, 7) such that f'(c) = 7- 1 This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f'(c) = f(7) – f(1) but f is not continuous at x = 3. 7- 1

Let f(x) = (x - 3)-2. Find all values of c in (1, 7) such that f(7) - f(1) = f'(c)(7 - 1). (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) C = Based off of this information, what conclusions can be made about the Mean Value Theorem? f(7) – f(1) 7 - 1 This contradicts the Mean Value Theorem since f satisfies the hypotheses on the given interval but there does not exist any c on (1, 7) such that f'(c) = This does not contradict the Mean Value Theorem since f is not continuous at x = 3. f(7) – f(1) This does not contradict the Mean Value Theorem since f is continuous on (1, 7), and there exists a c on (1, 7) such that f'(c) = 7- 1 This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f'(c) = f(7) – f(1) but f is not continuous at x = 3. 7- 1

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section5.3: The Natural Exponential Function

Problem 52E

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