Let f(x)=√3x-2 on the interval volume of the resulting solid. 83л (A - unit 3 135 83л (в -unit 3 125 43x -unit 3 135 43x -unit 3 125 C) D 2 1. Revolve the region between the curve, y=1 and y-axis about the y-axis and find the 1

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A: A detailed solution is given below.

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A: Using the Leibnitz rule:

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A: Given:   To determine: The minimum allowed length for the runway.

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A: We have to choose option find antiderivative

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A: We can solve this as follows:

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A: Given that,

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A: Always false

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A: Please see the below picture for detailed solution.

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A: We know eln(x) =x

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A: We have to determine proper rational functions and choose correct options

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A: Solve by integration

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A:

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A: The area bounded by fx=x2-x and x-axis

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A: Please follow the next step.

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A: What is the integrand

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A:

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A: The region is bounded by fx=ex, gx=e-x and x=3

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A:

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A: Using p-test form infinite limit we know that:  For a>0: If p>1 then ∫a∞1xpdx converges. Here…

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A: To evaluate the integral.

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A:

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A: On solving this we will get

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Q: Which of the following represents the volume of the solid generated by revolving the region bounded…

A: To evaluate the integral. Option A is correct.

Q: (x+1)x (x+2)(x-1)² If f @ 1/1 1/1/0 93 B C D 9 . - 2 3 2 9 3 - 2/3 . 93 A B 421 + + x+2 C (5-131].…

A: Explained below

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A: Let's find useful formula for evaluation of integration.

Q: Find the volume of solid generated by revolving the region bounded by f(x) = x² + 1and g(x)=x²+2x+…

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A: Solution: equation r=3

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A: C option is false

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A:

Q: Which of the following represents the volume of the solid generated by revolving the region bounded…

A: the line y=x-1and y=(x-1)3 intersect in the points (0,-1),(1,0) and (2,1) the line y=x-1 is below…

Q: Question 6 Determine the area bounded by the functions f(x) = (x + 1)³ and g(x)=x+1, A unit² Ⓡ®…

A: Just plot the graph and see which is above and below to each other and find intersection point