Let P(x) = x³ –- 2x² + 10x – 1.83 i) Evaluate P at x = 1.96 (use 4 digit rounding arithmetic). ii) Find the nested form Q (x) of P (x). %3D %3D iii) Evaluate Q at x =1.96 (use 4 digit rounding arithmetic) iv) Compute absolute error of P (1.96) and Q (1.96).

Let P(x) = x³ –- 2x² + 10x – 1.83 i) Evaluate P at x = 1.96 (use 4 digit rounding arithmetic). ii) Find the nested form Q (x) of P (x). %3D %3D iii) Evaluate Q at x =1.96 (use 4 digit rounding arithmetic) iv) Compute absolute error of P (1.96) and Q (1.96).

Name: Let P(x) = x³ –- 2x² + 10x – 1.83i) Evaluate P at x = 1.96 (use 4 dig
Uploaded: 2024-03-20T06:38:44.000Z
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Description: Let P(x) = x³ –- 2x² + 10x – 1.83i) Evaluate P at x = 1.96 (use 4 digit rounding arithmetic).ii) Find the nested form Q (x) of P (x).%3D%3Diii) Evaluate Q at x =1.96 (use 4 digit rounding arithmetic)iv) Compute absolute error of P (1.96) and Q (1.96