Let R be the region enclosed by the curves y = 1, y = ln x, and y = (x – 1)², shown below. (0. 1) ya1 (0,1) 08 y=ln(x) 0.6 R 04 ya(x-1) 02 (1, 0) Set up(and do not evaluate) a (sum of) definite integral(s) equal to: 1. The area of the region R using vertical strips. 2. The length of the graph of y = ln x from the point (1,0) to the point (e, 1). 3. The volume of the solid obtained when R is revolved around the line a = -1, using the method of washers.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter5: Graphs And The Derivative
Section5.3: Higher Derivatives, Concavity, And The Second Derivative Test
Problem 63E
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Please answer the third question. Thank you!

Let R be the region enclosed by the curves y = 1, y = ln x, and y = (x – 1)², shown below.
|(0, 1)
y=1
(e,1)
0.8
y=In(x)
0.6
R
04
y=(x-1)
0.2
02
0.4
06
0.8
1.6
1.8
2.6
2.8
(1, 0)
--02
Set up(and do not evaluate) a (sum of) definite integral(s) equal to:
1. The area of the region R using vertical strips.
2. The length of the graph of y = ln x from the point (1,0) to the point (e, 1).
3. The volume of the solid obtained when R is revolved around the line x = -1, using the
method of washers.
Transcribed Image Text:Let R be the region enclosed by the curves y = 1, y = ln x, and y = (x – 1)², shown below. |(0, 1) y=1 (e,1) 0.8 y=In(x) 0.6 R 04 y=(x-1) 0.2 02 0.4 06 0.8 1.6 1.8 2.6 2.8 (1, 0) --02 Set up(and do not evaluate) a (sum of) definite integral(s) equal to: 1. The area of the region R using vertical strips. 2. The length of the graph of y = ln x from the point (1,0) to the point (e, 1). 3. The volume of the solid obtained when R is revolved around the line x = -1, using the method of washers.
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ISBN:
9780321964038
Author:
GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:
Pearson Addison Wesley,